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Which of these formulas is correctly rewritten from the original formula to solve for c a equals 2b plus c?
c= a-2b
A equals 2b plus c Which of these formulas is correctly rewritten from the original formula to solve for c?
a-2b=c
A equals 2b plus c solve for b?
A = 2b + cSubtract 'c' from each side:A - c = 2bDivide each side by 2:b = 1/2 (A - c)
B2O3 plus Mg plus heat equals 2B plus MgO?
3Mgo+2B
A plus b plus c plus d plus e equals 30 where c plus e equals 14 and d equals b plus 1 and a equals 2b-1 and a plus c equals 10 find values of letters?
a+b+c+d+e = 30 (i) c+e = 14 (ii) d+b = 1 (iii) a = 2b-1 (iv) a+c = 10 (v) By (i)-(ii)-(iii): a = 15 then, by (iv): b = 8 and by (v): c = -5 Also, b = 8 so by (iii): d = -7 and then by (i), e = 19
What is the formula to solve for b a equals 2b plus c?
If: a = 2b+c Then: a-c = 2b And: b = (a-c)/2
For a equals 2b plus c what is the correct formula rewritten from the original formula to solve c?
a = 2b + c then a - 2b = c ie c = a - 2b
A plus b plus c equals 2s then 2s-2b is equal to?
2s-2b= a+b+c-2b simplified that would be a+c-b.
Which of these formulas is correctly rewritten from the original formula to solve for c a equals 2b plus c?
c= a-2b
A equals 2b plus c Which of these formulas is correctly rewritten from the original formula to solve for c?
a-2b=c
A equals 2b plus c solve for b?
A = 2b + cSubtract 'c' from each side:A - c = 2bDivide each side by 2:b = 1/2 (A - c)
B plus B equals?
=2b
If a plus a plus b plus b equals 26 and b plus b plus c equals 22 and c plus c plus c plus c plus b plus b equals 46 then a equals?
2a + 2b = 26 2b + c = 22 ===> b = 11 - c/2 4c + 2b = 46 ===> b = 23 - 2c From the 2nd and 3rd equations: 11 - c/2 = 23 - 2c 22 - c = 46 - 4c 22 - 46 = -4c + c ===> -24 = -3c ===> c = 8 Substitute c=8 into the 3rd equation: b = 23 - 16 = 7 Substitute b=7 into the 1st equation: 2a + 14 = 26 2a = 12 ===> a = 6
B2O3 plus Mg plus heat equals 2B plus MgO?
3Mgo+2B
When solving S equals a plus 2b for a you get a equals S - 2b?
4
A plus b plus c plus d plus e equals 30 where c plus e equals 14 and d equals b plus 1 and a equals 2b-1 and a plus c equals 10 find values of letters?
a+b+c+d+e = 30 (i) c+e = 14 (ii) d+b = 1 (iii) a = 2b-1 (iv) a+c = 10 (v) By (i)-(ii)-(iii): a = 15 then, by (iv): b = 8 and by (v): c = -5 Also, b = 8 so by (iii): d = -7 and then by (i), e = 19
What is c plus 2b plus c?
They are terms of an algebraic expression that can be simplified to: 2b+2c
