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Q: What is the relation between radius of a semicircle and a cone's volume?

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Let the radius of the sphere be r. surface area of the sphere = 4 * pi * r^2 volume = (4 * pi * r^3)/3

It is volume of a cylinder = pi*radius2*height or length

The volume is proportional to the cube of the height.

==================================Answer #2:I believe you want the volume of the shell ... the material between theinside and outside diameters ... whereas the first answer, above, gave youthe volume of the hole in the middle of everything. Here's my take on it:-- Volume of a sphere is 4/3 pi R3-- Volume enclosed by the outer radius is 4/3 pi (2)3-- Volume enclosed by the inner radius is 4/3 pi (1)3-- Volume of the material between them is4/3 pi (23 - 13) = 4/3 pi x 7 =28/3 pi = 29.32 m3. (rounded)The volume of a spherical shell is equal to the difference between the volume of a sphere with a radius of 2 m and a volume of a sphere with a radius of 1 meter:V= 29,321531433504736892318004910609 Ð¼3

A radius is a 1-dimensional object and so it has no volume.

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Let the radius of the sphere be r. surface area of the sphere = 4 * pi * r^2 volume = (4 * pi * r^3)/3

For any object, the mass is the product of its volume and its density. In the case of Earth, that would be the averagedensity. The volume, of course, can be calculated on the basis of its radius. Use the formula for a sphere; that's close enough for most purposes.

It is volume of a cylinder = pi*radius2*height or length

semicircle is a two-dimensional shape, hence it has an area but does not have a volume.

volume of the cube - volume of the sphere = volume enclosed between the cube and sphere

The volume is proportional to the cube of the height.

The relationship between the formulas is that in all the radius is cubed.

Robert Boylesee link

For Ideal gases, mole fraction=volume fraction

Density = mass divided by volume, measured in kg per cubic metre

==================================Answer #2:I believe you want the volume of the shell ... the material between theinside and outside diameters ... whereas the first answer, above, gave youthe volume of the hole in the middle of everything. Here's my take on it:-- Volume of a sphere is 4/3 pi R3-- Volume enclosed by the outer radius is 4/3 pi (2)3-- Volume enclosed by the inner radius is 4/3 pi (1)3-- Volume of the material between them is4/3 pi (23 - 13) = 4/3 pi x 7 =28/3 pi = 29.32 m3. (rounded)The volume of a spherical shell is equal to the difference between the volume of a sphere with a radius of 2 m and a volume of a sphere with a radius of 1 meter:V= 29,321531433504736892318004910609 Ð¼3

Doubling the radius quadruples the volume.

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