None, unless there is a relation between the semicircle and the cone that you have chosen not to share.
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Let the radius of the sphere be r. surface area of the sphere = 4 * pi * r^2 volume = (4 * pi * r^3)/3
It is volume of a cylinder = pi*radius2*height or length
The volume is proportional to the cube of the height.
==================================Answer #2:I believe you want the volume of the shell ... the material between theinside and outside diameters ... whereas the first answer, above, gave youthe volume of the hole in the middle of everything. Here's my take on it:-- Volume of a sphere is 4/3 pi R3-- Volume enclosed by the outer radius is 4/3 pi (2)3-- Volume enclosed by the inner radius is 4/3 pi (1)3-- Volume of the material between them is4/3 pi (23 - 13) = 4/3 pi x 7 =28/3 pi = 29.32 m3. (rounded)The volume of a spherical shell is equal to the difference between the volume of a sphere with a radius of 2 m and a volume of a sphere with a radius of 1 meter:V= 29,321531433504736892318004910609 м3
If the volume of the cylinder is 5, then its volume is 5 and its radius doesn't matter.