Let the radius of the sphere be r. surface area of the sphere = 4 * pi * r^2 volume = (4 * pi * r^3)/3
It is volume of a cylinder = pi*radius2*height or length
The volume is proportional to the cube of the height.
==================================Answer #2:I believe you want the volume of the shell ... the material between theinside and outside diameters ... whereas the first answer, above, gave youthe volume of the hole in the middle of everything. Here's my take on it:-- Volume of a sphere is 4/3 pi R3-- Volume enclosed by the outer radius is 4/3 pi (2)3-- Volume enclosed by the inner radius is 4/3 pi (1)3-- Volume of the material between them is4/3 pi (23 - 13) = 4/3 pi x 7 =28/3 pi = 29.32 m3. (rounded)The volume of a spherical shell is equal to the difference between the volume of a sphere with a radius of 2 m and a volume of a sphere with a radius of 1 meter:V= 29,321531433504736892318004910609 м3
If the volume of the cylinder is 5, then its volume is 5 and its radius doesn't matter.
Let the radius of the sphere be r. surface area of the sphere = 4 * pi * r^2 volume = (4 * pi * r^3)/3
For any object, the mass is the product of its volume and its density. In the case of Earth, that would be the averagedensity. The volume, of course, can be calculated on the basis of its radius. Use the formula for a sphere; that's close enough for most purposes.
It is volume of a cylinder = pi*radius2*height or length
volume of the cube - volume of the sphere = volume enclosed between the cube and sphere
The volume is proportional to the cube of the height.
The relationship between the formulas is that in all the radius is cubed.
A semi-circle is a two dimensional figure so it can have area but NOT volume. To find the area of a semi-circle see the question below.
==================================Answer #2:I believe you want the volume of the shell ... the material between theinside and outside diameters ... whereas the first answer, above, gave youthe volume of the hole in the middle of everything. Here's my take on it:-- Volume of a sphere is 4/3 pi R3-- Volume enclosed by the outer radius is 4/3 pi (2)3-- Volume enclosed by the inner radius is 4/3 pi (1)3-- Volume of the material between them is4/3 pi (23 - 13) = 4/3 pi x 7 =28/3 pi = 29.32 m3. (rounded)The volume of a spherical shell is equal to the difference between the volume of a sphere with a radius of 2 m and a volume of a sphere with a radius of 1 meter:V= 29,321531433504736892318004910609 м3
For Ideal gases, mole fraction=volume fraction
Density = mass divided by volume, measured in kg per cubic metre
The ancient Greek mathematician Archimedes proved that the volume of a sphere is four times that of the cone with base equal to a great circle of the sphere and height the radius of the sphere. Maybe this is what the poser of the question meant.
If the volume of the cylinder is 5, then its volume is 5 and its radius doesn't matter.