If the cell has a simple geometric shape, there are formulae that can be used. Otherwise you need to measure the surface area and the volume.
Yes.
It doesn't really matter whether the contents is liquid or otherwise. Formulae for several regular shapes are known - you can use one of them. If you don't find the formula for a specific shape, you can use integration. This is covered in introductory calculus books; roughly speaking, it means dividing the shape into small pieces, for example, small rectangles. That's how many of the well-known formulae are obtained, as well.
It means that the units are compatible with one another. For example, if the unit of length is the meter, the natural unit of volume is the cubic meter. That way, formulae like volume (of a rectangular box) = length x width x height or the well-known formula for the volume of a sphere will require no additional conversion factors. The same happens if the unit of length is the foot, and the volume is measured in cubic feet. However, if you measure lengths in feet and volume in gallons, then the units are not compatible (or coherent) with one another.
names and formulae how are they reconised
None, unless there is a relation between the semicircle and the cone that you have chosen not to share.
There are different formulae for their volume, surface area, mass, etc. You have not specified what formula and for what purpose.There are different formulae for their volume, surface area, mass, etc. You have not specified what formula and for what purpose.There are different formulae for their volume, surface area, mass, etc. You have not specified what formula and for what purpose.There are different formulae for their volume, surface area, mass, etc. You have not specified what formula and for what purpose.
pi * radius2 * height
peanut butter
There is no single formula for volume. Some simple shapes, such as a cuboid, sphere, cone, pyramid, prism have relatively simple, but different formulae. Other shapes have more complicated formulae.
The volume of a cube is V = x3. The derivative of this is (d/dV)x = 3x2.
There are different formulae for different solids such as spheres or polyhedra.
2/3*pi*r^2
Volume of a pyramid = 1/3*base area*height in cubic units
No, a semicircle is not a quadrilateral
Semicircle
There are different formulae for different polyhedra and these depend on what information about the polyhedron is given.