The expression "3p - 7 p 13" seems unclear due to the presence of "p" between "-7" and "13." If we assume it's a typo and you meant "3p - 7 + 13," then the resulting equation simplifies to (3p + 6). If "p" represents multiplication, you might mean "3p - 7p + 13," which simplifies to (-4p + 13). Please clarify if this interpretation is incorrect.
To find the equation for the statement "the quotient of a number and 7 is 13," we can let the number be represented by the variable ( x ). The equation can be written as ( \frac{x}{7} = 13 ). To solve for ( x ), multiply both sides by 7, resulting in ( x = 13 \times 7 ), which simplifies to ( x = 91 ).
2
To find the product of (3p + 7)(3p + 7), you can use the formula for the square of a binomial, which is ( (a + b)^2 = a^2 + 2ab + b^2 ). In this case, ( a = 3p ) and ( b = 7 ). Therefore, the product is: [ (3p)^2 + 2(3p)(7) + 7^2 = 9p^2 + 42p + 49. ] So, the final result is ( 9p^2 + 42p + 49 ).
Well since an equation has an equal sign it is 6+7=13
s=-7/4
2
does 7(9-3p) = 42p
4p+2 = 3p-7 4p-3p = -7-2 p = -9
3p+7 = 16+2p 3p-2p = 16-7 p = 9
s=-7/4
Well since an equation has an equal sign it is 6+7=13
3p - 8 = 13 - 4p : Add 4p to both sides 7p - 8 = 13 : Add 8 to both sides 7p = 21 : Divide both sides by 7 p = 3.
n - 13 = 7
3s and 3p, remember Cl has 7 valance electron. 3s^2 and 3p^5
-2p+7.
3h+13 = 7 3h = 7-13 3h = -6 h = -2
3p plus 7 equals 34, where P is equivalent to number 9.