The rule used in this input-output relationship appears to be dividing the input numbers by 3 to get the corresponding output numbers. This can be deduced by observing that 3 divided by 3 is 1, 15 divided by 3 is 5, 18 divided by 3 is 6, and 27 divided by 3 is 9. Therefore, the rule is to divide the input numbers by 3 to obtain the output numbers.
There are many functions where if your input is -2 the output is 13. The simplest is probably just adding 15. You could also square -2 (to get 4) and then add 9.
Supposing the input is n. Some of the infinitely many possible answers are: n + 15 2n + 13 3n + 11 4n + 9 and so on. or 1.5n + 14 2.5n + 12 or 19 - n 21 - 2n And then there are non-linear examples. The simpler ones are n2 + 13 n3 + 9 but there can be trigonometric or logarithmic or other functions.
A number is divisible by 15 if it is divisible by the prime factors of 15, that is, 5 and 3.
0.0159
The rule is 5, 10, 15 and so the next number will be 20+31 = 51
It could be add 15, or it could be multiply by 3 plus 1, for example.
There are many functions where if your input is -2 the output is 13. The simplest is probably just adding 15. You could also square -2 (to get 4) and then add 9.
15
The mechanical advantage is the ratio of the output force to the input force. MA = output/input (output force divided by the input force) For the example, 15N/30N gives the MA as 0.5 (one half).
The mechanical advantage is the ratio of the output force to the input force. MA = output/input (output force divided by the input force) For the example, 15N/30N gives the MA as 0.5 (one half).
The mechanical advantage is the ratio of the output force to the input force. MA = output/input (output force divided by the input force) For the example, 15N/30N gives the MA as 0.5 (one half).
The mechanical advantage is the ratio of the output force to the input force. MA = output/input (output force divided by the input force) For the example, 15N/30N gives the MA as 0.5 (one half).
The mechanical advantage of this machine is 0.5. This is calculated by dividing the output force (15 N) by the input force (30 N). This means that the machine reduces the force required by half to produce the desired output force.
The y value will equal 15, when x = 7
There's only one number that equals 15. The number is 15, and you might as well forget about ever finding another one. You may be asking: "How do I decide what two numbers to put into a machine so that 15 comes out of it ?" Before you can do that, you need to know exactly what goes on inside the machine ... what is the relationship between the input and the output. There is no general rule. You just have to use your brain every time. There's no way around it. Sorry.
L293D is having 20 pin IC and also 16 pin IC. description of 20 pin is: 1-enable 1 2- input 1 3- output 1 4,5,6,7,14,15,16,17- ground 8- output 2 9- input 2 10,20-vs 11-enable 2 12- input 3 13-output 3 18-output 4 19-input 4 description for 18 pin: 1-enable 1 2- input 1 3- output 1 4,5,12,13- ground 6-output 2 7- input 2 8,18-vs 9-enable 2 10-input 3 11-output 3 14-output 4 15-input 4
The operation appears to involve subtracting 1 from the quotient of each input number divided by 5. Specifically, for each input number ( x ), the output can be calculated as ( \text{output} = \frac{x}{5} + 3 ). For example, for the input 5, the output is ( \frac{5}{5} + 3 = 4 ). This pattern holds for all given input numbers.