Divide by 3
There are many functions where if your input is -2 the output is 13. The simplest is probably just adding 15. You could also square -2 (to get 4) and then add 9.
Supposing the input is n. Some of the infinitely many possible answers are: n + 15 2n + 13 3n + 11 4n + 9 and so on. or 1.5n + 14 2.5n + 12 or 19 - n 21 - 2n And then there are non-linear examples. The simpler ones are n2 + 13 n3 + 9 but there can be trigonometric or logarithmic or other functions.
A number is divisible by 15 if it is divisible by the prime factors of 15, that is, 5 and 3.
0.0159
7x3-5x4=(7x3)-(5x4)=(21)-(20)=1 I used the order of operations rule, PEMDAS
It could be add 15, or it could be multiply by 3 plus 1, for example.
There are many functions where if your input is -2 the output is 13. The simplest is probably just adding 15. You could also square -2 (to get 4) and then add 9.
15
The mechanical advantage is the ratio of the output force to the input force. MA = output/input (output force divided by the input force) For the example, 15N/30N gives the MA as 0.5 (one half).
The mechanical advantage is the ratio of the output force to the input force. MA = output/input (output force divided by the input force) For the example, 15N/30N gives the MA as 0.5 (one half).
The mechanical advantage is the ratio of the output force to the input force. MA = output/input (output force divided by the input force) For the example, 15N/30N gives the MA as 0.5 (one half).
The mechanical advantage is the ratio of the output force to the input force. MA = output/input (output force divided by the input force) For the example, 15N/30N gives the MA as 0.5 (one half).
The y value will equal 15, when x = 7
There's only one number that equals 15. The number is 15, and you might as well forget about ever finding another one. You may be asking: "How do I decide what two numbers to put into a machine so that 15 comes out of it ?" Before you can do that, you need to know exactly what goes on inside the machine ... what is the relationship between the input and the output. There is no general rule. You just have to use your brain every time. There's no way around it. Sorry.
L293D is having 20 pin IC and also 16 pin IC. description of 20 pin is: 1-enable 1 2- input 1 3- output 1 4,5,6,7,14,15,16,17- ground 8- output 2 9- input 2 10,20-vs 11-enable 2 12- input 3 13-output 3 18-output 4 19-input 4 description for 18 pin: 1-enable 1 2- input 1 3- output 1 4,5,12,13- ground 6-output 2 7- input 2 8,18-vs 9-enable 2 10-input 3 11-output 3 14-output 4 15-input 4
If you want to work in watts, convert 25dB to a scalling factor: 3dB = 2 x input 10dB = 10 x input 20dB = 100 x input ...25dB = 10 ^ (25/10) = 316.2 x input So the output is 15 Watts x 316.2 = 4.7kW If you want to work in dB, then convert 15 watts to dB: 10 * log |P| = dB = 10*log |15| = 11.76dB so the output is 11.76 + 25 = 36.76dB
A voltage amplifier (high input and output impedances) with a gain of 83.5 dB will amplify a signal of 1 millivolt to an output of 15 volts.