There is no specific rule. y = -sqrt(x) y = x - 12 y = -x/3 y = x2 - 84 are all possible.
y=m(x)+b
There are infinitely many rules. SOme of these are: y = x/80 y = 80/x y = x + 79 y = 81 - x y = sqrt(x+1) - 8
x2 - y2 = (x + y)(x - y) is an identity, not a function.
9
y = x/3
3x-y to the third becomes (x+x)+x-y*y*y the question is (3x-y)3
There is no specific rule. y = -sqrt(x) y = x - 12 y = -x/3 y = x2 - 84 are all possible.
y=m(x)+b
(x,y) --> (x,-y)
(x,y)-> (-y,x)
2 x 3 x 3 x y x y x y
(x=y) (y=-x)
There is no specific rule. Among the infinitely many possibilities are y = 5 (whatever x is) y = x + 4 y = 27x - 22 y = x2 + 4x y = 28x/4 - 2
There are infinitely many rules. SOme of these are: y = x/80 y = 80/x y = x + 79 y = 81 - x y = sqrt(x+1) - 8
If X and Y are the first two numbers, then the third must be = 67 - (X+Y)
f(x, y) = (x, -y)