The relationship between the input and output values can be determined by a mathematical function or rule. In this case, when the input is 1 and the output is 8, the rule could be represented as f(x) = 8x, where f(x) is the function and x is the input value. This means that the output is obtained by multiplying the input value (1) by 8.
It is not. Suppose the function is "add 7".Then an input of 1 gives an output of 1+7 = 8.Double the input to 2 and the output is 2+7 = 9Whereas simply halving the output gives 9/2 = 4.5So the question is based on false premises.
A VHDL program for an 8-to-3 priority encoder using data flow style can be implemented using the when-else construct. The encoder outputs a 3-bit binary representation of the highest-priority active input (from 7 to 0), while also providing an output for invalid conditions. Here’s a simple example: library IEEE; use IEEE.STD_LOGIC_1164.ALL; use IEEE.STD_LOGIC_ARITH.ALL; use IEEE.STD_LOGIC_UNSIGNED.ALL; entity priority_encoder is Port ( input : in STD_LOGIC_VECTOR(7 downto 0); output : out STD_LOGIC_VECTOR(2 downto 0); valid : out STD_LOGIC); end priority_encoder; architecture dataflow of priority_encoder is begin process(input) begin case input is when "00000000" => output <= "000"; valid <= '0'; when others => output <= "111"; -- Default output for higher priority valid <= '1'; if input(7) = '1' then output <= "111"; elsif input(6) = '1' then output <= "110"; elsif input(5) = '1' then output <= "101"; elsif input(4) = '1' then output <= "100"; elsif input(3) = '1' then output <= "011"; elsif input(2) = '1' then output <= "010"; elsif input(1) = '1' then output <= "001"; elsif input(0) = '1' then output <= "000"; end if; end case; end process; end dataflow; This code checks the input vector and determines the highest active bit, setting the output accordingly.
The operation appears to involve subtracting 1 from the quotient of each input number divided by 5. Specifically, for each input number ( x ), the output can be calculated as ( \text{output} = \frac{x}{5} + 3 ). For example, for the input 5, the output is ( \frac{5}{5} + 3 = 4 ). This pattern holds for all given input numbers.
This is a priority encoder. When the individual input lines are driven low, this chip outputs the index number of the highest-numbered input line that is low, in binary-encoded form, on its four output lines. If inputs 2 and 6 are both low, the output is 6 (1010). If 6 and 8 are both low, the output is 8. If 2, 6, and 8 are low, the output is 8. And so on.
An 8 to 1 multiplexer (MUX) is a digital switch that selects one of eight input lines and forwards the selected input to a single output line based on three selection lines. The logic diagram consists of eight input lines (I0 to I7), three selection lines (S0, S1, S2), and one output line (Y). The selection lines determine which input is connected to the output, with each combination of the selection lines corresponding to one of the input lines. The logic gates used in the diagram typically include AND, OR, and NOT gates to implement the necessary connections and selection logic.
Oh, dude, that's like a piece of cake! If the input is 2 and the output is 8, it's probably following a rule where the output is four times the input. So, like, you just multiply the input by 4 to get the output. Easy peasy, right?
f(x) = x - 8.
It is not. Suppose the function is "add 7".Then an input of 1 gives an output of 1+7 = 8.Double the input to 2 and the output is 2+7 = 9Whereas simply halving the output gives 9/2 = 4.5So the question is based on false premises.
L293D is having 20 pin IC and also 16 pin IC. description of 20 pin is: 1-enable 1 2- input 1 3- output 1 4,5,6,7,14,15,16,17- ground 8- output 2 9- input 2 10,20-vs 11-enable 2 12- input 3 13-output 3 18-output 4 19-input 4 description for 18 pin: 1-enable 1 2- input 1 3- output 1 4,5,12,13- ground 6-output 2 7- input 2 8,18-vs 9-enable 2 10-input 3 11-output 3 14-output 4 15-input 4
this shows you everything you need about them Pin Number Description 1 A Input Gate 1 2 B Input Gate 1 3 Y Output Gate 1 4 A Input Gate 2 5 B Input Gate 2 6 Y Output Gate 2 7 Ground 8 Y Output Gate 3 9 B Input Gate 3 10 A Input Gate 3 11 Y Output Gate 4 12 B Input Gate 4 13 A Input Gate 4 14 Positive Supply
If you are talking combinations, without binary number representations, then you are talking about a circuit that has a 1 output when any input is a 0. That is a 3 input NAND gate. If you are talking binary number representation, then you are talking about a circuit that has a 1 output when the inputs are 010, 001, or 000. Use a 3 to 8 decoder, with an OR gate on the low three outputs.
IC 7402 is different from the other type of IC like 7404,7408,7432 and 7400 when it is connected to have an output desired... if you noticed all i mentioned ic is connected from left to the right. input pin 1 and 2, output pin 3 input pin 4 and 5, output pin 6 input pin 13 and 12, output pin 11 input pin 10 and 9, output pin 8 while in nor gate, to have the desired output it must be connected from right to left... input pin 2 and 3, output pin 1 input pin 5 and 6, output pin 4 input pin 8 and 9, output pin 10 input pin 11 and 12, output pin 13
.8 or 80%i.e. The output is 80% of the input.
SerialParallelUSBFirewireEtherneteSATAPCIAGP
The output can be expressed mathematically as ( \text{Output} = 2 \times (\text{Input} + 3) ). This means you first add 3 to the input value and then multiply the result by 2. For example, if the input is 5, the output would be ( 2 \times (5 + 3) = 2 \times 8 = 16 ).
It is -7.
If you are using the VGA output, you need to plug a cable from the headphone output on the laptop to the audio input on the TV. Many newer TV's have a 1/8" input jack for just this purpose.