To calculate the derivate of a power, where both the base and the exponent are functions of x, requires a technique called logarithmic derivation. I'll leave the details to you; it is not particularly difficult. You can look up "logarithmic differentiation" in the Wikipedia for some examples.
2
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.
Write sec x as a function of sines and cosines (in this case, sec x = 1 / cos x). Then use the division formula to take the first derivative. Take the derivative of the first derivative to get the second derivative. Reminder: the derivative of sin x is cos x; the derivative of cos x is - sin x.
(cos x sin x) / (cos x sin x) = 1. The derivative of a constant, such as 1, is zero.
-1/(2*x2)
Write it as (1/3)x and take the derivative. You get (1/3)x0 = 1/3 * 1 = 1/3 ■
It is negative one divided by 4 multiplied by x to the power of 1.5 -1/(4(x^1.5))
-1/x2
2
0.3333
(1/2(x^-1/2))/x
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.
Negative the derivative of f(x), divided by f(x) squared. -f'(x) / f²(x)
Well if you have 5/X then you can rewrite this like 5x-1. And the derivative to that is -5x-2 and that can be rewrote to: -(5/x2).
Write sec x as a function of sines and cosines (in this case, sec x = 1 / cos x). Then use the division formula to take the first derivative. Take the derivative of the first derivative to get the second derivative. Reminder: the derivative of sin x is cos x; the derivative of cos x is - sin x.
y=x^pid/dx=pi*(x^pi-1)This is true because of power rule.d/dx (x^a)=a(x^(a-1))
The derivative of a log is as follows: 1 divided by xlnb Where x is the number beside the log Where b is the base of the log and ln is just the natural log.