The secret number must be a two-digit number greater than 25 and less than 50. Since the tens digit is odd, it can be 3, 5, or 7. However, the sum of the digits must be less than 10, so the only possible tens digit is 3. The units digit can be any number from 0 to 9 that, when added to 3, results in a sum less than 10. Therefore, the secret number is 31.
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No, a 4-digit number is not always less than a 5-digit number. The value of a number is determined by the digits it contains, not the number of digits. For example, the 4-digit number 9999 is greater than the 5-digit number 1000. It is important to consider the actual numerical value when comparing numbers, not just the number of digits.
A 6-digit number will ALWAYS be greater than a 5-digit number. Assuming both are positive of course.
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For now, I'll assume for simplicity that the numbers are positive. The number with the greatest amount of integer digits (before the decimal point, if any) is larger. If both numbers have the same number of integer digits, compare each digit in turn until you find one digit that is different. The number with the largest digit in this place is larger. Examples: 1234 is greater than 430, because it has more digits. 125 is greater than 117, because in the first digit they differ (second position from left), it has the greater digit. 0.007 is greater than 0.0009, because in the third digit to the right of the decimal point (the first digit where they differ), it has the greater digit (7 is greater than 0).
The 2-digit number must be 20, because it is the only 2-digit number whose sum of its two even digits, 2 + 0 = 2, is greater than the product of its two even digits, 2 x 0 = 0. Moreover, 20 is a product of the two consecutive integers 4 and 5.