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51
There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2
Fibonacci numbers are the numbers in a sequence defined as follows: N1 = 1 N2 = 1 and after that, each number is the sum of the last two numbers in the sequence. N3 = N1 + N2 N4 = N2 + N3 and so on.
It appears to be increasing in difference by 2. The nth number is n2 +2. 1*1+2=3 2*2+2=6 3*3+2=11
The sequence is too short for a definitive answer. One possibility is Un = n2 - 2n + 2 for n = 1, 2, 3, ... another is Un = (n3 - n + 6)/6 or Un = (n3 - 3n2 + 5)/3 There are many more.
51
There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2
Fibonacci numbers are the numbers in a sequence defined as follows: N1 = 1 N2 = 1 and after that, each number is the sum of the last two numbers in the sequence. N3 = N1 + N2 N4 = N2 + N3 and so on.
No, the coefficient sequence is not needed to balance the chemical equation for the reaction between magnesium (Mg) and nitrogen (N2) to form magnesium nitride (Mg3N2). The balanced chemical equation is already given as: 3Mg + N2 → Mg3N2.
Un = n3 + n2 - 3n - 2 for n = 1, 2, 3, ...
To find the nth term of a sequence, we first need to identify the pattern. In this case, the sequence appears to be increasing by consecutive odd numbers: 2, 4, 6, 8, and so on. This means the nth term can be represented by the formula n^2 + 2. So, the nth term for this sequence is n^2 + 2.
n2
It is T(n) = n2 - 2n + 6
n2-3n+2
(1/2n-r)2+((n2+2n)/4) where n is the row number and r is the position of the term in the sequence
Well, well, well, looks like we're playing a little game of "let's mess with the numbers." This sequence seems to be jumping all over the place like a kangaroo on a sugar rush. Let's break it down: 25, 26, 24, 27, 23. Looks like each number is just doing its own thing, no rhyme or reason.
(N2) + 3(H2) = 2(NH3)