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51
There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2
Fibonacci numbers are the numbers in a sequence defined as follows: N1 = 1 N2 = 1 and after that, each number is the sum of the last two numbers in the sequence. N3 = N1 + N2 N4 = N2 + N3 and so on.
It appears to be increasing in difference by 2. The nth number is n2 +2. 1*1+2=3 2*2+2=6 3*3+2=11
a0= 1 , a1=2, an= n2+1I'm sure there are more. This is the simplest one I could think of.
51
There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2There are infinitely many possible functions that can generate this sequence. One such isUn = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2
Fibonacci numbers are the numbers in a sequence defined as follows: N1 = 1 N2 = 1 and after that, each number is the sum of the last two numbers in the sequence. N3 = N1 + N2 N4 = N2 + N3 and so on.
No, the coefficient sequence is not needed to balance the chemical equation for the reaction between magnesium (Mg) and nitrogen (N2) to form magnesium nitride (Mg3N2). The balanced chemical equation is already given as: 3Mg + N2 → Mg3N2.
Un = n3 + n2 - 3n - 2 for n = 1, 2, 3, ...
Well, honey, the nth term for that sequence is n^2 + 2. Just plug in the value of n and you'll get your next number in the sequence. Keep it simple, darlin'.
n2
It is T(n) = n2 - 2n + 6
n2-3n+2
(1/2n-r)2+((n2+2n)/4) where n is the row number and r is the position of the term in the sequence
Well, well, well, looks like we're playing a little game of "let's mess with the numbers." This sequence seems to be jumping all over the place like a kangaroo on a sugar rush. Let's break it down: 25, 26, 24, 27, 23. Looks like each number is just doing its own thing, no rhyme or reason.
(N2) + 3(H2) = 2(NH3)