Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
The given sequence is the sequence of perfect squares starting from 1. The nth term of this sequence can be represented as n^2. Therefore, the 8th term would be 8^2, which equals 64. So, the 8th term of the sequence 1, 4, 9, 16, 25 is 64.
The nth term is: 5-6n
The nth term is 9n-2
Give me a answer
Please note that (a) this is a sequence of square numbes, and (b) the sequence starts at 22.
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
The given sequence is the sequence of perfect squares starting from 1. The nth term of this sequence can be represented as n^2. Therefore, the 8th term would be 8^2, which equals 64. So, the 8th term of the sequence 1, 4, 9, 16, 25 is 64.
The nth term is: 5-6n
The nth term is 25-4n and so the next term will be 5
It is 4n+5 and so the next term will be 25
The nth term is 9n-2
Give me a answer
It is: 27-2n
36 Seems like: 1 4 9 16 25 is squared sequence: 1 2 3 4 5 So 6 squared will be 36.
(n+1)^2 Please tell me you know what that means.
Divide the sequence by 5 and the answer becomes very obvious: 1, 4, 9, 16,...N2 So, 5, 20, 45, 80,...5N2