n2
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
The nth term is: 5-6n
t(n) = 28-3n where n = 1,2,3,...
The nth term is 9n-2
Well, darling, the sequence you've got there is just the perfect squares of numbers. The 8th term would be the square of the 8th number, which is 64. So, the 8th term of the sequence 1, 4, 9, 16, 25 is 64. Keep those brain cells sharp, honey!
To determine the nth term of the sequence 25, 16, 7, we first identify the pattern. The sequence appears to be decreasing by 9, then by 9 again, suggesting a consistent difference. This leads to a formula for the nth term: ( a_n = 34 - 9n ), where ( a_1 = 25 ) for n=1. Thus, the nth term can be expressed as ( a_n = 34 - 9n ).
Please note that (a) this is a sequence of square numbes, and (b) the sequence starts at 22.
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
The nth term is: 5-6n
t(n) = 28-3n where n = 1,2,3,...
It is 4n+5 and so the next term will be 25
The nth term is 9n-2
Well, darling, the sequence you've got there is just the perfect squares of numbers. The 8th term would be the square of the 8th number, which is 64. So, the 8th term of the sequence 1, 4, 9, 16, 25 is 64. Keep those brain cells sharp, honey!
Give me a answer
The sequence given is an arithmetic sequence where each term increases by 6. To find the nth term, you can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. Here, ( a_1 = 7 ) and ( d = 6 ). Thus, the nth term can be expressed as ( a_n = 7 + (n-1) \times 6 = 6n + 1 ).
It is: 27-2n
36 Seems like: 1 4 9 16 25 is squared sequence: 1 2 3 4 5 So 6 squared will be 36.