Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
The 8th term is 64. The sequence is the squares of the counting numbers. The nth term is given by t(n) = n².
The nth term is: 5-6n
5^n
The nth term is 9n-2
Please note that (a) this is a sequence of square numbes, and (b) the sequence starts at 22.
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
The 8th term is 64. The sequence is the squares of the counting numbers. The nth term is given by t(n) = n².
The nth term is: 5-6n
The nth term is 25-4n and so the next term will be 5
5^n
It is 4n+5 and so the next term will be 25
The nth term is 9n-2
It is: 27-2n
36 Seems like: 1 4 9 16 25 is squared sequence: 1 2 3 4 5 So 6 squared will be 36.
(n+1)^2 Please tell me you know what that means.
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.