n2
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
The nth term is: 5-6n
t(n) = 28-3n where n = 1,2,3,...
The nth term is 9n-2
Well, darling, the sequence you've got there is just the perfect squares of numbers. The 8th term would be the square of the 8th number, which is 64. So, the 8th term of the sequence 1, 4, 9, 16, 25 is 64. Keep those brain cells sharp, honey!
Please note that (a) this is a sequence of square numbes, and (b) the sequence starts at 22.
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
The nth term is: 5-6n
t(n) = 28-3n where n = 1,2,3,...
It is 4n+5 and so the next term will be 25
The nth term is 9n-2
Well, darling, the sequence you've got there is just the perfect squares of numbers. The 8th term would be the square of the 8th number, which is 64. So, the 8th term of the sequence 1, 4, 9, 16, 25 is 64. Keep those brain cells sharp, honey!
Give me a answer
It is: 27-2n
36 Seems like: 1 4 9 16 25 is squared sequence: 1 2 3 4 5 So 6 squared will be 36.
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
(n+1)^2 Please tell me you know what that means.