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There are infinitely many possible functions that can generate this sequence. One such is

Un = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2

There are infinitely many possible functions that can generate this sequence. One such is

Un = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2

There are infinitely many possible functions that can generate this sequence. One such is

Un = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2

There are infinitely many possible functions that can generate this sequence. One such is

Un = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2

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11y ago

There are infinitely many possible functions that can generate this sequence. One such is

Un = (n2 - 3n + 2)/2 = (n-2)*(n-1)/2

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Q: What is the nth term in this sequence 0 0 1 3 6 10?
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This is an arithmetic progression. In general, If an A.P. has a first term 'a', and a common difference 'd' then the nth term is a + (n - 1)d. In the sequence shown in the question, the first term is 0 and the common difference is 5, therefore the nth term is, 0 + (n - 1)5. This can be rearranged to read : 5(n - 1) For example : the 7th term is 30 : 5(7 - 1) = 5 x 6 = 30.


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