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5.7735026918962... The formula for the area of a hexagon is A=.5ap, or
A=(1/2)ap, where A=area, a=apothem, and p=perimeter. This means that, because the area is 100, 100=.5ap, so 200=ap. Because in a regular hexagon the apothem is equal to the side length, what we are really saying here is that 200=6a2. Therefore, 33.333=a2, or a= about 5.77. This is the side length.
What else can I help you with?
Is ht of hexogon2ht of square?
Not if the hexagon is a regular hexagon with sides of the same length as the sides of the square.
A square whose sides each measure ten centimeters can completely fit inside of a regular hexagon whose sides each measure ten centimeters?
Yes, a square with sides measuring ten centimeters can completely fit inside a regular hexagon with sides also measuring ten centimeters. The hexagon's interior angles and the distances from the center to the vertices allow for a square to be inscribed within it, as the square's diagonal is shorter than the hexagon's width at its widest points. Specifically, the diagonal of the square is approximately 14.14 centimeters, which is less than the distance between opposite sides of the hexagon. Thus, the square can be accommodated within the hexagon without any overlap.
Can a square whose sides each measure ten centimeters can completely fit inside of a regular hexagon whose sides each measure ten centimeters?
Yes, easily.
Can a regular hexagon be tessellated?
Yes. A regular tessellation can be created from either an equilateral triangle, a square, or a hexagon.
Area of the regular hexagon whose side length is 16 in and apothem is 8 square root 3 in?
It is 665.1 sq inches.
Is ht of hexogon2ht of square?
Not if the hexagon is a regular hexagon with sides of the same length as the sides of the square.
Can a square whose sides each measure 10 centimeters fit inside a regular hexagon whose sides each measure 10 centimeters?
Well, honey, let me break it down for you. A square with sides measuring 10 centimeters each can definitely fit inside a regular hexagon with sides also measuring 10 centimeters. The square's diagonal would be 14.14 centimeters, which is less than the hexagon's side length. So, technically, it's a perfect fit!
What is the area of a regular hexagon with a side length of 2 centimeter and an apothem length of 10.4 centimeters?
Such a hexagon is impossible. A regular hexagon with sides of 2 cm can have an apothem of sqrt(3) cm = approx 1.73.It seems you got your question garbled. A regular hexagon, with sides of 2 cm, has an area of 10.4 sq cm. If you used your measurement units properly, you would have noticed that the 10.4 was associated with square units and it had to refer to an area, not a length.
A square whose sides each measure ten centimeters can completely fit inside of a regular hexagon whose sides each measure ten centimeters?
Yes, a square with sides measuring ten centimeters can completely fit inside a regular hexagon with sides also measuring ten centimeters. The hexagon's interior angles and the distances from the center to the vertices allow for a square to be inscribed within it, as the square's diagonal is shorter than the hexagon's width at its widest points. Specifically, the diagonal of the square is approximately 14.14 centimeters, which is less than the distance between opposite sides of the hexagon. Thus, the square can be accommodated within the hexagon without any overlap.
What is the area of a regular hexagon with a side length of 12 centimeters and an apothem length of 10.4 centimeters?
Abbreviations:A = Areap =Perimetera = apothemx = times (as in multiply)A = 1/2(ap)A = 1/2 (10.4 x 72)A = 1/2 (748.8)A = 374.4 square centimeters
Area of a hexagon?
Length of one side squared x 1.5 x square root of 3, for a REGULAR hexagon.
Square whose sides each measure ten centimeters can completely fit inside of a regular hexagon whose sides each measure ten centimeters?
yes
A regular hexagon has an apothem length of 14 m. What is the area of the hexagon Round to the nearest whole number?
It is 679 square metres.
What is the formula of area of a hexagon?
For a regular hexagon it is: area_regular_hexagon = 3/2 × √3 × side_length²
Can a square whose sides each measure ten centimeters can completely fit inside of a regular hexagon whose sides each measure ten centimeters?
Yes, easily.
Can a regular hexagon be tessellated?
Yes. A regular tessellation can be created from either an equilateral triangle, a square, or a hexagon.
What shape has all sides the same lenght?
Any "regular" polygon has all sides the same length. -- equilateral triangle -- square -- regular pentagon -- regular hexagon . . etc.
