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What is the area of a regular hexagon with a side length of 12 centimeters and an apothem length of 10.4 centimeters?
Wiki User
∙ 11y ago
Abbreviations:A = Area
p =Perimeter
a = apothem
x = times (as in multiply)
A = 1/2(ap)
A = 1/2 (10.4 x 72)
A = 1/2 (748.8)
A = 374.4 square centimeters
Wiki User
∙ 11y ago
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What is the apothem of a regular hexagon with sides of 16 inches?
We know that the height of an equilateral triangle equals the product of one half of the side length measure with square root of 3.Since in our regular hexagon we form 6 equilateral triangles with sides length of 16 inches, the apothem length equals to 8√3 inches.
How do you find the area of a hexagon without a side length?
To find the area of a Regular hexagon with side length (x) you need:1. The "radius" of the hexagon. (Just the length from the center to the outside edge.)2. The apothem. (which is only just half of the height of the base.)**If you don't have one or both of these you can't do it.**Steps:1. Make a triangle of the apothem (used as a) and the radius. (r)2. Use the Pythagorean Theorem to find 1 half of the side length.3. Multiply the actual side length by 6.4. Multiply that by a.5. The area is your answer.
How do you find the apothem of a hexagon with only the side length?
The apothem is the radial distance from the middle of the side to the centre of the hexagon. A hexagon is six congruent equilateral triangles joined by adjacent sides. Equilateral triangles can be divided into two equal right angled triangles. The upright of the right angled triangle is effectively the apothem of the original hexagon. Pythagoras now kicks in. The apothem (vertical) is A and half the side length (base) is B, the third (longest) side is C and is the same as the original side length. Pythagoras states A2 + B2 = C2. So by transposition, A = root (C2 - B2). As B = 1/2 C, the apothem A is given by: A = root(C2 - (C/2)2) = root(C2 - C2/4) = root(3C2/4) = C x root(3) / 2 So the apothem of a hexagon is 1/2 x root(3) x the side length.
What is the area of a regular heptagon with a side length of 8 in. and an apothem of 8.3 in.?
232.57 square inches.
What is the area of a regular octagon with a side length of 4 inches and an apothem length of 4.8 inches?
By joining all the vertices to the centre of the octagon, the apothem forms the height of the triangles with the side of the regular octagon as the base. This the area is 8 × area_triangles = 8 × ½ × side × apothem = 4 × side × apothem: Area_regular_octagon = 4 × side_length × apothem ≈ 4 × 4 in × 4.8 in = 76.8 in²
What is the apothem of a regular hexagon?
If the hexagon has side length s, then the apothem is sqrt(3) * s / 2.
What is the area of a regular hexagon with a side length of 2 centimeter and an apothem length of 10.4 centimeters?
Such a hexagon is impossible. A regular hexagon with sides of 2 cm can have an apothem of sqrt(3) cm = approx 1.73.It seems you got your question garbled. A regular hexagon, with sides of 2 cm, has an area of 10.4 sq cm. If you used your measurement units properly, you would have noticed that the 10.4 was associated with square units and it had to refer to an area, not a length.
What is the side length of a regular hexagon with area 100 square centimeters?
5.7735026918962... The formula for the area of a hexagon is A=.5ap, or A=(1/2)ap, where A=area, a=apothem, and p=perimeter. This means that, because the area is 100, 100=.5ap, so 200=ap. Because in a regular hexagon the apothem is equal to the side length, what we are really saying here is that 200=6a2. Therefore, 33.333=a2, or a= about 5.77. This is the side length.
What is the area of a regular hexagon with apothem length of 24 inches?
For a regular hexagon, half the side length can be calculated from the apothem via trigonometry: half_side_length = apothem x tan 30° Then: area = apothem x 1/2 x perimeter = apothem x 1/2 x side_length x 6 = apothem x half_side_length x 6 = 24 in x (24 in x tan 30°) x 6 ≈ 1995 sq in
What is the area of a regular octagon with a side length of 5.8 centimeters and an apothem length of 7 centimeters?
An octagon with a side length of 5.8 cm has an apothem that is approximately 7 cm. The area of such a shape is approx 162.4 sq cm.
What is the apothem of a regular hexagon with sides of 16 inches?
We know that the height of an equilateral triangle equals the product of one half of the side length measure with square root of 3.Since in our regular hexagon we form 6 equilateral triangles with sides length of 16 inches, the apothem length equals to 8√3 inches.
A regular hexagon has an apothem length of 14 m. What is the area of the hexagon Round to the nearest whole number?
It is 679 square metres.
What is the area of a regular octagon with a side length of 5.8 centimeters and a apothem of 7 centimeters?
An octagon with a side length of 5.8 cm has an apothem that is approximately 7 cm. The area of such a shape is approx 162.4 sq cm.
Area of the regular hexagon whose side length is 16 in and apothem is 8 square root 3 in?
It is 665.1 sq inches.
Find the area of the regular hexagon described in the question above?
Let s be the length of a side of the hexagon and let h be the the apothem 6(1/2sh) it the area of 3sh.
If the apothem of a regular pentagon is 10.8 centimeters then what is the length of a side of the pentagon?
it aould be 10.8 divided by five ok
The apothem of a regular pentagon is 10.8 centimeters. What is the length of a side of the pentagon?
regular pentagon area of 12 000 m2 and an apothem of 40 m regular pentagon area of 12 000 m2 and an apothem of 40 m need to figure it out from area 12000 m2
