The side length is 70.71 cm
Cool question ! Answer - half it then cube it to prove it - an example for you if cube diagonal (not square diagonal) is 100, then using pythagoras theorm the square diagonal = 70.71068, If square the square diagonal = 70.71068, then using pythagoras theorm the side length = 50 therefore the volume = 50 ^ 3 = 25000 units works with any numbers
So the diagonal of the square will be 10m Use Pythagoras' theorem to find the length x of the square: x2+x2 = 100 2x2 = 100 Divide both sides by 2: x2 = 50 Square root both sides: x = 7.071067812 Therefore: length of one side = 7.071067812 meters
The length of the diagonal which is to opposite of 100⁰ angle is: diagonal length = √[152 + 82 - 2(15)(8)cos 100⁰] diagonal length ≈ 18 The length of the diagonal which is to opposite of 100⁰ angle is: diagonal length =√[152 + 82 - 2(15)(8)cos 80⁰] diagonal length ≈ 16
To find the diagonal of a rectangle, you can use the Pythagorean theorem, which states that the square of the hypotenuse (diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal (d) is the hypotenuse, and the length (l) and width (w) are the other two sides. So, d^2 = l^2 + w^2. Plugging in the values, we get d^2 = 6^2 + 8^2 = 36 + 64 = 100. Therefore, the diagonal is the square root of 100, which is 10.
18.9 feet
If the area of a square is 100, then its side length is 10. If we draw in a diagonal, then we know by the Pythagorean formula that the diagonal's length is sqrt(10^2 + 10^2) = sqrt(200) = 10*sqrt(2).The square root of 2 is approximately 1.414, so the diagonal's length is approximately 10*1.414 =14.14* The diagonal of any square is the side length times (sq rt 2).
If the circle is inscribed in the square, the side length of the square is the same as the diameter of the circle which is twice its radius: → area_square = (2 × 5 in)² = 10² sq in = 100 sq in If the circle circumscribes the square, the diagonal of the square is the same as the diameter of the circle; Using Pythagoras the length of the side of the square can be calculated: → diagonal = 2 × 5 in = 10 in → side² + side² = diagonal² → 2 × side² = diagonal² → side² = diagonal² / 2 → side = diagonal / √2 → side = 10 in / √2 → area _square = (10 in / √2)² = 100 sq in / 2 = 50 sq in.
Using Pythagoras' theorem which says that the square on the hypotenuse (in this case the diagonal) is equal to the sum of the squares on the other two sides (which in the case of a square would be equal in length). so if the diagonal measured 10 units, the square on the diagonal would be 100 square units. And as this = 2*the squares on the other sides, the square on one side would be 100/2 = 50 square units. As a square has sides of equal length the square on one side is actually the area of the square. i.e. the area of a square with a diagonal of 10 units is 50 square units. or generically the area of a square with a diagonal of length 'x' = (x2)/2
Cool question ! Answer - half it then cube it to prove it - an example for you if cube diagonal (not square diagonal) is 100, then using pythagoras theorm the square diagonal = 70.71068, If square the square diagonal = 70.71068, then using pythagoras theorm the side length = 50 therefore the volume = 50 ^ 3 = 25000 units works with any numbers
So the diagonal of the square will be 10m Use Pythagoras' theorem to find the length x of the square: x2+x2 = 100 2x2 = 100 Divide both sides by 2: x2 = 50 Square root both sides: x = 7.071067812 Therefore: length of one side = 7.071067812 meters
The length of the diagonal which is to opposite of 100⁰ angle is: diagonal length = √[152 + 82 - 2(15)(8)cos 100⁰] diagonal length ≈ 18 The length of the diagonal which is to opposite of 100⁰ angle is: diagonal length =√[152 + 82 - 2(15)(8)cos 80⁰] diagonal length ≈ 16
The length of each side of the smaller squares is 2.475 cm
To find the diagonal of a rectangle, you can use the Pythagorean theorem, which states that the square of the hypotenuse (diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal (d) is the hypotenuse, and the length (l) and width (w) are the other two sides. So, d^2 = l^2 + w^2. Plugging in the values, we get d^2 = 6^2 + 8^2 = 36 + 64 = 100. Therefore, the diagonal is the square root of 100, which is 10.
If the quadrilateral is a square then all of its sides are the same length. ac is not one of the sides but is a diagonal which forms the hypotenuse of a right angle triangle with sides ab and bc. According to Pythagoras the sum of the square of the hypotenuse is equal to the sum of the squares of the other two sides. As side ab measures 10 then 10 squared = 100. Side bc has the same measurements. The square of side ac must equal 200 (100 + 100) so the length of side ac must equal the square root of 200 (100 + 100) which is 14.14 (to 2 decimal places).
A square with a side length of 10 inches has an area of 100 square inches.
18.9 feet
25 !