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What is the perimeter of 2 yd by 5 yd?
The Answer To This Question Is : p = 2xl + 2xw p = 2x2+ 2x5 p = 4 + 10 p = 14 !
What is the formula for a rectangle?
Perimeter: (length: 5 inches; width: 5 inches) P= (2xL) + (2xW) P= (2x5) + (2x5) P= 10 + 10 P= 20 Area (length: 5 inches; width: 5 inches) A= LxW A= 5 x 5 A= 25
What would be the perimeter of a rectangle 9cm 5cm?
The formula for perimeter is P=2XL+2XW which is Perimeter = 2 X length + 2 X Width. We want to replace L and W with the the numbers 9 and 5. I don't know which is which but lets say the 9 is the length and 5 is the width. So the new number sentence would be P=2X9+2X5. So now it's time to solve. 2X9=18. 2X5=10. 10+18=28. Your perimeter would be 28cm. Hope this helped! :)
A rectangular box is created from a piece of posterboard which is 24'' long and 9'' wide by cutting out identical squares from the corners and then turning up the sides Find the dimensions of the box?
First we need to find the side length of the square we cut in order to maximize the volume of the box. Let the side of the square be x.Volume = lwhl = 24 - 2xw = 9 - 2xh = xV = (24 - 2x)(9 - 2x)(x)V = [(24)(9)(x) - (24)(2x)(x) - (2x)(9)(x) - (2x)(-2x)(x)]V = 216x - 48x^2 - 18x^2 + 4x^3V = 216x - 60 x^2 + 4x^3 Take the derivativeV' = 216 - 120x + 12x^2 Make the derivative equal to 00 = 216 - 120x + 12x^20 = 12(18 - 10x + x^2)0 = 18 - 10x + x^2x = [10 ± √[(10^2 - 4(1)(18)]]/2x = (10 ± √28)/2x = (10 ± 2√7)/2x = 5 ± √7 = x = 5 ± 2.6x = 7.6 or x = 2.4 this are critical values, which we substitute into volume equationV = 216(2.4) - 60(2.4^2) + 4(2.4^3) = 228 in^3Thus, the side length of the square we cut is 2.4 in, which also is the height of the box. So,l = 12 - 2(2.4) = 12 - 4.8 = 7.2w = 9 - 2(2.4) = 9 - 4.8 = 4.2Or we can estimate and say that the box will be 7 inches long, 4 inches wide, and 2 inches high.
