I'm going to assume a few things...
1.) the 2s after a letter are 2
2.) this is addition, because it's easier for me and if you wanted another operation, you should have stated so.
2a2b+a2+5ab+3ab2+b2+2a2b+2ab
4ab+a2+5ab+3b2a+b2+4ab+2ab
15ab+3b2a+a2+b2
( 2ab ) is.
2ab-6bc = -4
The GCF is 2ab.
No, ab squared is not the same as 2ab. ab squared (ab^2) means multiplying ab by itself, resulting in a^2 * b^2. On the other hand, 2ab means multiplying 2 by a and then by b, resulting in 2ab. These two expressions are not equivalent because ab^2 involves squaring the variable b, while 2ab does not involve squaring any variables.
2ab - 3b2 - 3b + 2a does not have a solution, as it is not an equation.
let binomial be (a + b)now (a+b)3 will be (a+b)(a+b)2 = (a+b)(a2 + 2ab+ b2) = a(a2+ 2ab+ b2) + b(a2 + 2ab+ b2) = a3+ 2a2b+ ab2 + a2b + 2ab2 + b3 = a3+ 2a2b+ ab2 + a2b + 2ab2 + b3 = a3 +3a2b + 3ab2 +b3 hope it helped... :D
To factorize the expression 4ab - 6ab, you first need to identify the common factor between the two terms, which is 2ab. You can then factor out this common factor to rewrite the expression as 2ab(2 - 3). Therefore, the fully factorized form of 4ab - 6ab is 2ab(2 - 3) or simply -2ab.
It is an expression
( 2ab ) is.
-2ab
An expression.
a2b2 - 2ab - 25 is a quadratic expression in the variables ab. There is no equation or inequality in the question so there is nothing that can be solved. Because of the nature of the expression a and b cannot be separated in any meaningful way.
Algebraically:((a+b) / 2) / ((a+b) / (2ab)) = 2ab(a + b) / 2(a + b) = (2a2b + 2ab2) / (2a + 2b) = abAs an example, let a = 2 and b = 3 then:i) (a + b) / 2 = (2 + 3) / 2 = 5/2ii) (a + b) / (2 * a * b) = (2 + 3) / (2 * 2 * 3) = 5 / 12Therefore i) is ab times larger than ii). (for these specific example numbers it will be 6 times larger)
The given terms can be simplified to: a -b
(2a + 3)(b - 3c)
2ab-6bc = -4
2ab-2 = 0