First, you need to find the slope of the line we're given:
2x = 12y + 4
∴ x = 6y + 3
∴ 6y = x - 3
∴ y = x/6 - 3
By that we can see that the slope of the line given is 1/6. To find the slope that is perpendicular, all you need to do reverse that fraction. Instead of 1/6, it would be 6/1. So the answer to your question is 6.
The slope is -0.2
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
-1/5
the slope will be positive 1.5x the whole equation is y=4.5+1.5x
It is -1/2
12
The slope is -0.2
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
-1/5
It is: -1/2
It is: 1/5
negative 1
-5
the slope will be positive 1.5x the whole equation is y=4.5+1.5x
It is -1/2
- 1/3
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3