You have to get your equation into slope intercept form. Slope intercept form is y=mx+b
Now use algebra on your equation to get "y" on the left side and "x" and the numbers on the right side..
2y = 5 - 8x
y = -(8/2)x + (5/2)
y = -4x + 2.5
Now it is slope intercept form. In the previous y=mx+b equation your m=slope
Therefore in your equation m=-4 so your slope is -4/1
This means it go down four units and left one unit. This is rise over run.
-4
Rewrite the equation in the form y = mx + c and then m is the slope. Thus: 2y = -8x + 5 and then y = -4x + 5/2 So the slope is the coefficient of x, which is -4.
2y = 8x - 3 divide by 2 to both sidesy = 4x - 3/2 (this is the slope-intercept form of the equation, where slope is 4)The slope is 4.
(1, 1)
8x+2y=4x=-y/4+0.5y=-4x+2
the slope of the line is -4
-4
-4
Rewrite the equation in the form y = mx + c and then m is the slope. Thus: 2y = -8x + 5 and then y = -4x + 5/2 So the slope is the coefficient of x, which is -4.
-4
2y = 8x - 3 divide by 2 to both sidesy = 4x - 3/2 (this is the slope-intercept form of the equation, where slope is 4)The slope is 4.
(1, 1)
8x+2y=4x=-y/4+0.5y=-4x+2
16X - 2Y = 4- 2Y = - 16X + 4Y = 8X - 2---------------m(slope) = 8===========
Rewrite the equation is the slope-intercept form: 2y = 8x + 16 Divide through by the coefficient of y: y = 4x + 8 The slope is the coefficient of x, ie 4.
8x + 2y = 1 Rearrange in to straight line form 'y = mx + c'. 'm' is the slope/gradient of the line 'c' is the y intersept. Hence 2y = -8x + 1 y = -4x + 1/2 So slope is '-4'. and y-intercept is '1/2' 4
x=7 and y=4