Q: What is the slope of the line containing the origin and (-5-6)?

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You can calculate 13 + 56, and 13 - 56.

This produces a straight line, which is proven by solving our statement: -7x - 4 = 52 -7x = 56 x = -8 Thus, x has an undefined (uncountable) slope, and passes through all points (-8,y), such that y is a real number. In words, this is a vertical line passing through (-8,y).

Same number above and below the line 2 / 2 = 1 56 / 56 = 1 and so on ...

1, 8, 28, 56, 70, 56, 28, 8, 1 I hope that helps

26 = 64 and 56 = 15625

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If you mean: y - 5 = -3(x - 17) then:The slope is -3 and the line passes through the point (17, 5).It can be rearranged into y = -3x + 56 to also give the slope of -3 and the y-intercept of 56

The simplest way is to rewrite the equation in the standard for: y = mx + c. Then the slope is m. 8x - 7y = 56 7y = 8x - 56 y = 8/7 * x - 8 So the slope is 8/7

Points: (8, 8) and (1, 2) Slope: (8-2)/(8-1) = 6/7 Equation: y-8 = 6/7(x-8) => 7y-56 = 6x-48 => 7y = 6x-48+56 Slope intercept form: 7y = 6x+8

A number of point lies on it...................(-2,-44), (-1,-19),(0,6), (1,31), (2, 56)...............

If you mean: y-5 = -3(x-17) then y = -3x+56 whereas -3 is the slope and 56 is the y intercept

rokothana 56

You can calculate 13 + 56, and 13 - 56.

11.8 % steps are: 56 / 473.2 ( how much Liters in a 1pint )* 100= 11.8

This produces a straight line, which is proven by solving our statement: -7x - 4 = 52 -7x = 56 x = -8 Thus, x has an undefined (uncountable) slope, and passes through all points (-8,y), such that y is a real number. In words, this is a vertical line passing through (-8,y).

1, 8, 28, 56, 70, 56, 28, 8, 1 I hope that helps

Same number above and below the line 2 / 2 = 1 56 / 56 = 1 and so on ...

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