If you mean: y - 5 = -3(x - 17) then:
If you mean: y-5 = -3(x-17) then y = -3x+56 whereas -3 is the slope and 56 is the y intercept
If you mean: y+3 = -4(x-5) then y = -4x+17 whereas the slope of the line is -4 and the y intercept is 17
Without an equality sign the expression given can't be considered to be a straight line equation
First find the slope of the given line . 5x + 8y =17 Put this into the 'y = mx + c '. form. Hence 8y = -5x + 17 y =(-5/8)x +17/8 '-5/8' is the slope of the given line. To find the perpendicular slope use the equation mm' = -1 Hence substituting (-5/8)m' = -1 m' = (-1)(-8/5) (Note the inversion of the numbers) m' = 8/5 (Note the double negative multiplies out to a positive), = 1 3/5 = 1.6 is the slope of the perpendicular line.
y=3x+b -2=3*5+b b=-17 y=3x-17
write an equation that has a slope 7 and passes through the point (2,17)
17/12
y=-18x+17. Since this is already in Slope-Intercept form, we can determine that the slope is negative 18.
Without an equality sign the given terms can't be considered to be a straight line equation.
If you mean: y-5 = -3(x-17) then y = -3x+56 whereas -3 is the slope and 56 is the y intercept
If you mean: y+3 = -4(x-5) then y = -4x+17 whereas the slope of the line is -4 and the y intercept is 17
-17/23 and the intercept is 25/23
Without an equality sign the expression given can't be considered to be a straight line equation
Points: (12, 8) and (17, 16) Slope: 8/5 Equation: 5y = 8x-32
First find the slope of the given line . 5x + 8y =17 Put this into the 'y = mx + c '. form. Hence 8y = -5x + 17 y =(-5/8)x +17/8 '-5/8' is the slope of the given line. To find the perpendicular slope use the equation mm' = -1 Hence substituting (-5/8)m' = -1 m' = (-1)(-8/5) (Note the inversion of the numbers) m' = 8/5 (Note the double negative multiplies out to a positive), = 1 3/5 = 1.6 is the slope of the perpendicular line.
If you mean: 11x+2y = 34 then y = -10.5x+17 whereas -10.5 is the slope and 17 is the y intercept of a straight line equation
If you mean: y = -2x+17 then the perpendicular slope line is 1/2 or 0.5