To find the slope of the line containing the points (3, 1) and (-1, 3), use the formula for slope ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Here, ( (x_1, y_1) = (3, 1) ) and ( (x_2, y_2) = (-1, 3) ). Plugging in the values, we get ( m = \frac{3 - 1}{-1 - 3} = \frac{2}{-4} = -\frac{1}{2} ). Thus, the slope of the line is (-\frac{1}{2}).
Points: (6, 6) and (2, 13)Slope of line: -7/4
If you mean points of (1, 3) and (3, 7) then the slope works out as 2
17
Y=2x+3 (I'm 13 and I knew that
undefined
First we note that the slope does exist between the two points because the two points do not have the same x co-ordinate. Next, we apply the slope formula. slope=(y2-y1)/(x2-x1) Note that it does not matter which point you call as 1 or 2, you will still get the same result. For this example we will call point (-5,-13) as point 1 and (-17,-19) as point 2. Therefore: slope=(-19-(-13)) / (-17-(-5)) = (-6) / (-12) = 1/2 Therefore, the slope of the line containing the points (-5,-13) and (-17,-19) is 1/2.
Points: (6, 6) and (2, 13)Slope of line: -7/4
If you mean points of (1, 3) and (3, 7) then the slope works out as 2
If you mean points of (3, 9) and (1, 3) then the slope is 3
Parallel lines have the same slope. The slope of the second line is also 13.
17
If you mean points of: (1, 3) and (7, 5) then the slope works out as 1/3
Y=2x+3 (I'm 13 and I knew that
undefined
Infinite. The line is perpendicular to the ordinate.
If you mean points of (1, 6) and (-5, -7) the slope works out as 13/6
If we call the slope m we can say that the slope of the perpendicular line is -1/m In this case as the slope, m, is 13 the slope of the perpendicular is -1/13 or -0.07692307692