the slope of the line is -4
16
Let (x1, y1) = (-1, -6) and (x2, y2) = (-2, 10). Then the slope,m = (y2 - y1)/(x2 - x1) = (10 - -6)/(-2 - -1) = 16/-1 = -1/16.So that the point-slope form of the equation of the given line is:(y - y1) = m(x - x1)(y - -6) = (-1/16)(x - -1)(y + 6) = (-1/16)(x + 1)
Points: (12, 8) and (17, 16) Slope: 8/5 Equation: 5y = 8x-32
To function form. - 7X - 4Y = 16 - 4Y = 7X + 16 Y = - 7/4X - 4 ------------------------ The slope is, - 7/4 --------
the slope of the line is -4
Slope of a line perpendicular to x-y=16
-14
If you mean x-y = 16 then y = x-16 and the slope of the line parallel to it is 1 and it will have a different y intercept
That will depend on what (185) represents but the slope of a line is (y2-y1)/(x2-x1)
The slope would be 3/4
1.6x - 3.2y = 16 3.2y = 1.6x - 16 y = 0.5x - 5 So slope = coefficient of x = 0.5
16
-14
If you mean: y = 5x+16 then the y intercept is 16 and the slope is 5
Slope = change in ordinate/change in abscissa = (2 - 16)/(4 - -3) = -14/7 = -2
-4 apexvs