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What is the slope of the line 8x plus 2y equals 16?
the slope of the line is -4
The slope of the best fit line is -2.5 Find the y-intercept of this line 212 37 54?
16
What is the point slope form of the equation of the line through -1 -6 and -2 10?
Let (x1, y1) = (-1, -6) and (x2, y2) = (-2, 10). Then the slope,m = (y2 - y1)/(x2 - x1) = (10 - -6)/(-2 - -1) = 16/-1 = -1/16.So that the point-slope form of the equation of the given line is:(y - y1) = m(x - x1)(y - -6) = (-1/16)(x - -1)(y + 6) = (-1/16)(x + 1)
What is the equation of the line that passes through the points (12 8) and (17 16)?
Points: (12, 8) and (17, 16) Slope: 8/5 Equation: 5y = 8x-32
What is the slope of -7x-4y equals 16?
To function form. - 7X - 4Y = 16 - 4Y = 7X + 16 Y = - 7/4X - 4 ------------------------ The slope is, - 7/4 --------
What is the slope of the line 8x plus 2y equals 16?
the slope of the line is -4
Find the slope of a line perpendicular to x - y equals 16?
Slope of a line perpendicular to x-y=16
What is the slope of a line parallel to 2x-y equals 16?
-14
What is a Slope of a line parallel to x-y16?
If you mean x-y = 16 then y = x-16 and the slope of the line parallel to it is 1 and it will have a different y intercept
What is the slope of a line that passes through (-8-16) and(185)?
That will depend on what (185) represents but the slope of a line is (y2-y1)/(x2-x1)
What is the slope of the line whose equation is 3x-4y-16 equals 0?
The slope would be 3/4
What is the slope of a line parallel to 1.6x-3.2y equals 16?
1.6x - 3.2y = 16 3.2y = 1.6x - 16 y = 0.5x - 5 So slope = coefficient of x = 0.5
The slope of the best fit line is -2.5 Find the y-intercept of this line 212 37 54?
16
Find the slope of a line perpendicular to 2x-y equals 16?
-14
What is the y-intercept of the line given by the equation y5x 16?
If you mean: y = 5x+16 then the y intercept is 16 and the slope is 5
What is the slope intercept form of the equation for the line that passes through the point (-10-6) and has a slope of -1?
The slope-intercept form of a line is given by the equation ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope ( m = -1 ) and a point (-10, -6), we can substitute these values into the equation to find ( b ): [ -6 = -1(-10) + b \implies -6 = 10 + b \implies b = -16. ] Thus, the slope-intercept form of the line is ( y = -x - 16 ).
How do i Calculate the slope of a line that passes through the points (4 2) and (-3 16)?
Slope = change in ordinate/change in abscissa = (2 - 16)/(4 - -3) = -14/7 = -2
