That line is vertical. Its slope is "undefined".
Points: (1, -2) and (-1, -6) Slope: (-2--6)/1--1) = 2
The straight line equation for a line with a slope of 6 that goes through (1,2) works out as: y = 6x-4
-1
Points: (-2, -3) and (-6, -5) Slope: -1/2
1/6
Points: (2, 6) and (-1, -6)Slope: 4
Points: (1, -2) and (-1, -6) Slope: (-2--6)/1--1) = 2
Points: (2, 6) and (-1, -6)Slope: 4
The straight line equation for a line with a slope of 6 that goes through (1,2) works out as: y = 6x-4
-1
Points: (-2, -3) and (-6, -5) Slope: -1/2
Points: (-6, -7) and (6, 5) Slope: (-7-5)/(-6-6) = 1
1/6
If you mean points of (6, -2) and (-3, 7) then the slope works out as -1
If you mean points of (6, -2) and (-3, 7) then the slope works out as -1
Points: (2, -6) and (-3, 1) Slope: (-6-1)/(2--3) = -7/5 or -1.4
Well. Slope intercept is y= mx + b. With B being the y intercept. If it contains 1,1 and the slope is positive 6, do the equation 1 = 6 (1) + b. 1 = 6 + b -5 = b. So the answer is y = 6x - 5