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What is the slope of the line that contains the points (-25) and (6-3)?
Wiki User
∙ 6y ago
If you mean points of (6, -2) and (-3, 7) then the slope works out as -1
Christelle Borer
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What is the slope of the line containing (-25)?
If you mean (-2, 5) then another coordinate is needed in order to determine the slope of the line
What is the slope of the line 10x plus 5y equals 25?
10x+5y = 25 5y = -10x+25 y = -2x+5 Therefore: the slope is -2 and the intercept is 5
How do you determine if three points are collinear?
Since any 2 points determine 1 line, take 2 of the points and find the equation of the line drawn thru these 2 points. Substitute the x and y of the either point into the equation and find the y-intercept (b) Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are =. (y2-y1) ÷ (x2 - x1) = slope y = slope * x + b Point # 1 = (6, 5) Point # 2 = (10, 25) Point # 3 = (12, 30) Point # 4 = (12, 35) (y2 - y1) ÷ (x2 - x1) = slope (25 - 5) ÷ (10 - 6) = slope (20) ÷ (4) = slope Slope = 5 y = m * x + b y = 5 * x + b Substitute the x and y of the point (6, 5) into the equation and find the y-intercept (b) y = 5 * x + b 5 = 5 * 6 + b 5 = 30 + b b = -25 y = 5 * x - 25 . Check your points Point # 1 = (6, 5) 5 = 5 * 6 - 25 5 = 30 - 25 OK . Point # 2 = (10, 25) 25 = 5 * 10 - 25 25 = 5 * 10 - 25 OK . Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are Point # 3 = (12, 30) . y = 5 * x - 25 30 = 5 * 12 - 25 30 = 60 - 25 = 35 Point # 3 = (12, 30) is not on the line . . Point # 4 = (12, 35) 35 = 5 * 12 - 25 35 = 60 - 25 =35 Point # 4 = (12, 35) is on the line
Given the equation of a line y 25x - 2 the slope and y-intercept are respectively?
23
How do you convert .25 inch per foot into degrees or percent slope?
To express .25 inch per foot as a percent slope multiply rise over run times 100. This can be expressed rise/run x 100. rise=.25 inch run=12inches. So .25 divided by 12 times 100 equals 2.083 which can be rounded to 2.1 or simply 2% slope
What is the slop of the line that contains the points (-25) and (6-3)?
If you mean points of: (-2, 5) and (6, -3) then the slope works out as -1
What is the equation and its perpendicular bisector equation of the line joining the points of -7 -3 and -1 -4 on the Cartesian plane showing key stages of work?
The key stages of the work are the following:1) Find the slope for the line that joins the given points.2) Divide -1 by this slope to get the slope of the perpendicular line.3) Find the midpoint (calculate the averages of the x-coordinates and of the y-coordinates).4) Use the point-slope equation of the line to find a line with the desired slope, that goes through the desired point.Another Answer:-Points: (-7, -3) and (-1, -4)Mdpoint: (-4,-3.5)Slope: -1/6Perpendicular slope: 6Equation: 6y = -x-25 or as x+6y+25 = 0Perpendicular bisector equation: y = 6x+20.5 or as 6x-y+20.5 = 0
What is the slope of (-25) and (-57)?
32
What is the slope of the line containing (-25)?
If you mean (-2, 5) then another coordinate is needed in order to determine the slope of the line
What is an equation of a line passing through (25) and (-41)?
Points: (2, 5) and (-4, 1) Slope: 2/3 Equation: 3y = 2x+11
What equation in slope intercept form represents the line that passes though the two points (25) (92)?
If you mean points: (2, 5) and (9, 2) then it works out as y = -3/7x+41/7
What is the equation of this line (01)(25)(37)?
If you mean points of (0, 1) (2, 5) (3, 7) Then the slope is 2 The equation works out as: y = 2x+1
How do you Complete the equation of the line through ( 3 and minus 1 ) ( 4 7 )?
Points: (3, -1) and (4, 7) Slope: 8 Equation: y = 8x-25
What is the slope of the line 10x plus 5y equals 25?
10x+5y = 25 5y = -10x+25 y = -2x+5 Therefore: the slope is -2 and the intercept is 5
What is the slope of 6 -10 -15 15?
Points: (6, -10) and (-15, 15) Slope: (-10-15)/(6--15) = -25/21
How do you determine if three points are collinear?
Since any 2 points determine 1 line, take 2 of the points and find the equation of the line drawn thru these 2 points. Substitute the x and y of the either point into the equation and find the y-intercept (b) Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are =. (y2-y1) ÷ (x2 - x1) = slope y = slope * x + b Point # 1 = (6, 5) Point # 2 = (10, 25) Point # 3 = (12, 30) Point # 4 = (12, 35) (y2 - y1) ÷ (x2 - x1) = slope (25 - 5) ÷ (10 - 6) = slope (20) ÷ (4) = slope Slope = 5 y = m * x + b y = 5 * x + b Substitute the x and y of the point (6, 5) into the equation and find the y-intercept (b) y = 5 * x + b 5 = 5 * 6 + b 5 = 30 + b b = -25 y = 5 * x - 25 . Check your points Point # 1 = (6, 5) 5 = 5 * 6 - 25 5 = 30 - 25 OK . Point # 2 = (10, 25) 25 = 5 * 10 - 25 25 = 5 * 10 - 25 OK . Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are Point # 3 = (12, 30) . y = 5 * x - 25 30 = 5 * 12 - 25 30 = 60 - 25 = 35 Point # 3 = (12, 30) is not on the line . . Point # 4 = (12, 35) 35 = 5 * 12 - 25 35 = 60 - 25 =35 Point # 4 = (12, 35) is on the line
What is the slope of the line with equation 17x plus 23y equals 25?
-17/23 and the intercept is 25/23
