The straight line equation for a line with a slope of 6 that goes through (1,2) works out as: y = 6x-4
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
y=2x+1
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
That line is vertical. Its slope is "undefined".
If you mean points of (4,-1) and (-1, 4) then the slope of the line works out as -1
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
y=2x+1
Point: (2, -1) Slope: -5 Equation: y = -5x+9
y-1 = 3(x - 2)
y = 2x - 1
y = 2x + 1
If you mean points of: (-1, -1) and (3, 5) then the slope is 3/2 or 1.5
Another point is needed to work out the slope and its straight line equation. Slope is worked out as: (y2-y1)/(x2-x1) ----------------------- With slope m and going through a point (x0, y0), a line has equation: y - y0 = m(x - x0) Thus the point-slope equation of a line with slope m through the point (-1, 2) is given by: y - 2 = m(x - -1) → y - 2 = m(x + 1)
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
If you mean points of (-1, 9) and (5, 21) then the slope works out as 2
y=2x+1