Another set of points are needed to work out the slope which is: y1-y2/x1-x2
If you mean points of (-3, 6) and (4, 2) then the slope works out as -4/7
If you mean: (3, 6) and (4, 2) then it works out as -4/3
If you mean points of (-3, 6) and (4, 6) then it works out that the slope is 0
If you mean points of (3, 6) and (1, -2) then the slope is 4
The slope of any line parallel to the line described is -5. Solution: 45x+9y=36. Solve for y. 9y=36-45x. y= -5x+4 m=-5
If you mean points of (-3, 6) and (4, 2) then the slope works out as -4/7
If you mean: (3, 6) and (4, 2) then it works out as -4/3
It is: y-4 = 5(x-8) => y = 5x-36 which is a straight line equation
If you mean points of (-3, 6) and (4, 6) then it works out that the slope is 0
If you mean points of (3, 6) and (1, -2) then the slope is 4
If you mean points of (20, 15) and (48, 36) then its slope is 3/4 and equation 4y = 3x And the equation of (-4, -3) with a slope of 3/4 is also 4y = 3x
The slope of any line parallel to the line described is -5. Solution: 45x+9y=36. Solve for y. 9y=36-45x. y= -5x+4 m=-5
Points: (-2, 7) and (3, 6) the slope is -1/5 Points: (4, 2) and (9, 1) the slope is -1/5 Both slopes are the same and so therefore they are parallel lines
17/12
-36
A minimum of 1, a maximum of 36.
To find the equation of a line in standard form (Ax + By = C) that passes through the point (-5, 1) with a slope of 7, we can use the point-slope form first: (y - 1 = 7(x + 5)). Simplifying this gives (y - 1 = 7x + 35) or (y = 7x + 36). Rearranging to standard form results in (-7x + y = 36) or (7x - y = -36). Thus, the standard form of the equation is (7x - y = -36).