Q: What is the slope of the line through the points 36 and 42?

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If you mean points of (-3, 6) and (4, 2) then the slope works out as -4/7

Another set of points are needed to work out the slope which is: y1-y2/x1-x2

Points: (-2, 7) and (3, 6) the slope is -1/5 Points: (4, 2) and (9, 1) the slope is -1/5 Both slopes are the same and so therefore they are parallel lines

If you mean points of (-3, 6) and (4, 6) then it works out that the slope is 0

If you mean points of (3, 6) and (1, -2) then the slope is 4

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If you mean points of (-3, 6) and (4, 2) then the slope works out as -4/7

Another set of points are needed to work out the slope which is: y1-y2/x1-x2

If you mean points of (20, 15) and (48, 36) then its slope is 3/4 and equation 4y = 3x And the equation of (-4, -3) with a slope of 3/4 is also 4y = 3x

Points: (-2, 7) and (3, 6) the slope is -1/5 Points: (4, 2) and (9, 1) the slope is -1/5 Both slopes are the same and so therefore they are parallel lines

If you mean points of (-3, 6) and (4, 6) then it works out that the slope is 0

If you mean points of (3, 6) and (1, -2) then the slope is 4

The slope of any line parallel to the line described is -5. Solution: 45x+9y=36. Solve for y. 9y=36-45x. y= -5x+4 m=-5

17/12

A line in the X-Y plane follows an equation y = (slope X x) plus a constant k. In this instances, 5 = [(-12)(3)] + k, or k = 5 + 36 = 41. Therefore, the equation is: y = -12x + 41.

-36

A minimum of 1, a maximum of 36.

this is not a valid equation. I assume you mean: 2X+8Y=36 in which case the graph is a line with a slope of 1/4 and a y-intercept at 9/2 or 2X+4Y+2=36 in which case the graph is still a line with a slope of 1/2 and a y-intercept at 17/2