It is: y-4 = 5(x-8) => y = 5x-36 which is a straight line equation
For example, if the slope at a certain point is 1.5, you can draw a line that goes through the specified point, with that slope. The line would represent the slope at that point. If you want to graph the slope at ALL POINTS, take the derivative of the function, and graph the derivative. The derivative shows the slope of a function at all points.
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
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If you mean a slope of 2 and a point of (1, 4) then the equation is y = 2x+2
If the graph of the function is a continuous line then the function is differentiable. Also if the graph suddenly make a deviation at any point then the function is not differentiable at that point . The slope of a tangent at any point of the graph gives the derivative of the function at that point.
As a straight line equation: y = -3x+18 in slope intercept form
A derivative of a function represents that equation's slope at any given point on its graph.
A derivative of a function represents that equation's slope at any given point on its graph.
For example, if the slope at a certain point is 1.5, you can draw a line that goes through the specified point, with that slope. The line would represent the slope at that point. If you want to graph the slope at ALL POINTS, take the derivative of the function, and graph the derivative. The derivative shows the slope of a function at all points.
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
A single point cannot determine the slope of a straight line. It can, therefore, have any slope at all.
It depends. If voltage is drawn along the horizontal axis, then the slope at any point on the graph represents the reciprocal of resistance at that point. If current is drawn along the horizontal axis, then the slope at any point on the graph represents the resistance at that point.
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
Point: (2, -1) Slope: -5 Equation: y = -5x+9
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
If you mean a point of: (2,1) then the equation works out as y = 3x-5
The graph of a linear function is a line with a constant slope. The graph of an exponential function is a curve with a non-constant slope. The slope of a given curve at a specified point is the derivative evaluated at that point.