If you mean points of: (-1, 8) and (5, -4) then the slope is -2
To find the slope between the points (-20, -18) and (19, 5), use the slope formula: ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the values, we get ( m = \frac{5 - (-18)}{19 - (-20)} = \frac{5 + 18}{19 + 20} = \frac{23}{39} ). Therefore, the slope of the line connecting these two points is ( \frac{23}{39} ).
Points: (20, 18) and (35, 6) Slope: -4/5 Equation: y = -4/5x+34
Of course. If the line rises 18 units for every 27 horizontal units,then its slope is 2/3 .
To find the slope of the line represented by the equation (2x + 3y = 18), you can rearrange it into slope-intercept form (y = mx + b), where (m) is the slope. Starting with the original equation, isolate (y): [ 3y = -2x + 18 ] [ y = -\frac{2}{3}x + 6 ] From this, the slope (m) is (-\frac{2}{3}).
As a straight line equation: y = -3x+18 in slope intercept form
Points: (-3, 5) and (4, 7) Slope: 2/7
If you mean points of (055, 18) and (566, 81) then the slope works out as 9/73
If you mean points of (-10, -6) and (-1, 8) then the slope of the line is 14/9 which is in a positive direction
To find the slope between the points (-20, -18) and (19, 5), use the slope formula: ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the values, we get ( m = \frac{5 - (-18)}{19 - (-20)} = \frac{5 + 18}{19 + 20} = \frac{23}{39} ). Therefore, the slope of the line connecting these two points is ( \frac{23}{39} ).
Points: (20, 18) and (35, 6) Slope: -4/5 Equation: y = -4/5x+34
Points: (-18, -7) and (-20-9) Slope works out as 1
Of course. If the line rises 18 units for every 27 horizontal units,then its slope is 2/3 .
It is: y = 6x+18 whereas 6 is the slope and 18 is the y intercept
(3, 18), (3, 18) is just one point: it does not define a line.
To find the slope of the line represented by the equation (2x + 3y = 18), you can rearrange it into slope-intercept form (y = mx + b), where (m) is the slope. Starting with the original equation, isolate (y): [ 3y = -2x + 18 ] [ y = -\frac{2}{3}x + 6 ] From this, the slope (m) is (-\frac{2}{3}).
The "point slope" formula would be used. This is Y-Y1=m(X-X1) where Y1 and X1 are points the line passes through. M is the slope, so to find the slope of a line perpendicular, take it's opposite reciprocal which would be -8x/9. So Y-(-8)=-8/9(X-18) distribute -8/9 into X-18 and add the 8 on the left side of the = to get the slope intercept form.
Points: (13, 19) and (23, 17) Midpoint: (18, 18) Slope: -1/5 Perpendicular slope: 5 Perpendicular equation: y-18 = 5(x-18) => y = 5x-72