To find the slope of the line that passes through the points ((a-b)) and ((-a-b)), we first clarify that these points are actually ((a, -b)) and ((-a, -b)). The slope (m) is calculated using the formula (m = \frac{y_2 - y_1}{x_2 - x_1}). Substituting the points, we have (m = \frac{-b - (-b)}{-a - a} = \frac{0}{-2a} = 0). Thus, the slope of the line is 0, indicating a horizontal line.
Slope of perpendicular line is the negative reciprocal. So it is -1/4
0.5
negative 1/2
In symbolic form, line ( ab ) is typically represented as ( \overleftrightarrow{ab} ). This notation indicates that line ( ab ) extends infinitely in both directions through points ( a ) and ( b ). Alternatively, if referring to a segment between points ( a ) and ( b ), it can be denoted as ( \overline{ab} ).
line segment, line ab, __ ab
Any line that is parallel to another line will have the same slope. So if line AB's slope is zero and line CD is parallel to AB, then its slope will also be zero. The slope of line CD, when perpendicular to AB, will be infinity. If line AB has a slope of zero that means its just a horizontal line passing some point on the y-axis. A line that is perpendicualr to this one will pass through some point on the x-axis and therefore have an infinite slope.
3
The slope of line AB will be 1/2. Two parallel lines will always have the same slope, so if you know the slope of one line that is parallel to another, you know the other line's slope.
Slope of perpendicular line is the negative reciprocal. So it is -1/4
Given a straight line joining the points A and B, the perpendicular bisector is a straight line that passes through the mid-point of AB and is perpendicular to AB.
-1/2 or -0.50
0.5
The perpendicular bisector of a line segment AB is the straight line perpendicular to AB through the midpoint of AB.
negative 1/2
If the lines AB and CD are parallel then they both will have the same slope of -8 but with different y intercepts
If point a has coordinates (x1,y1), and point b has coordinates (x2, y2), then the slope of the line is given by the formula: m = (y2-y1)/(x2-x1).
y = ab^2+bx+c at point (1,2) y' = x since y' is also known as the slope, write the equation of point (1,2) at slope = X y- 2 = x (x-1) y= x^2-x+2 a=1 b=-1 c=2