0
To find the slope of the line that passes through the points ((a-b)) and ((-a-b)), we first clarify that these points are actually ((a, -b)) and ((-a, -b)). The slope (m) is calculated using the formula (m = \frac{y_2 - y_1}{x_2 - x_1}). Substituting the points, we have (m = \frac{-b - (-b)}{-a - a} = \frac{0}{-2a} = 0). Thus, the slope of the line is 0, indicating a horizontal line.
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Slope of a line AB is 4 what is the slope of CD if CD is perpendicular to AB?
Slope of perpendicular line is the negative reciprocal. So it is -1/4
Are ab and bc on the same line?
To determine if segments AB and BC are on the same line, you need to check if points A, B, and C are collinear. This can be confirmed by examining if the slope of AB is equal to the slope of BC. If the slopes are the same, then segments AB and BC lie on the same line. Otherwise, they are not collinear.
What is the equation of a line passing through the point (a b) and having a slope of b?
The equation of a line in point-slope form is given by ( y - y_1 = m(x - x_1) ), where ( m ) is the slope and ( (x_1, y_1) ) is a point on the line. For the point ( (a, b) ) and slope ( b ), the equation becomes ( y - b = b(x - a) ). Simplifying this, we get ( y = bx - ab + b ) or ( y = bx - ab + b ).
If AB contains the points 6 -2 and -3 16 what is the slope of a line perpendicular to AB?
0.5
If line ab contains points 4 19 and -3 5 what is the slope of a line perpenduiclar to lineab?
negative 1/2
Suppose the slope of AB is zero what is the slope of CD given that a. CD is parallel to AB b. CD is perpendicular to AB?
Any line that is parallel to another line will have the same slope. So if line AB's slope is zero and line CD is parallel to AB, then its slope will also be zero. The slope of line CD, when perpendicular to AB, will be infinity. If line AB has a slope of zero that means its just a horizontal line passing some point on the y-axis. A line that is perpendicualr to this one will pass through some point on the x-axis and therefore have an infinite slope.
The slope of line ab is 3 what is the slope of line CD if CD is parallel to ab?
3
If AB is parallel to CD and the slope of CD is one over two what is the slope of AB?
The slope of line AB will be 1/2. Two parallel lines will always have the same slope, so if you know the slope of one line that is parallel to another, you know the other line's slope.
Slope of a line AB is 4 what is the slope of CD if CD is perpendicular to AB?
Slope of perpendicular line is the negative reciprocal. So it is -1/4
What is a characteristic of a perpendicular bisector?
Given a straight line joining the points A and B, the perpendicular bisector is a straight line that passes through the mid-point of AB and is perpendicular to AB.
Are ab and bc on the same line?
To determine if segments AB and BC are on the same line, you need to check if points A, B, and C are collinear. This can be confirmed by examining if the slope of AB is equal to the slope of BC. If the slopes are the same, then segments AB and BC lie on the same line. Otherwise, they are not collinear.
What is the equation of a line passing through the point (a b) and having a slope of b?
The equation of a line in point-slope form is given by ( y - y_1 = m(x - x_1) ), where ( m ) is the slope and ( (x_1, y_1) ) is a point on the line. For the point ( (a, b) ) and slope ( b ), the equation becomes ( y - b = b(x - a) ). Simplifying this, we get ( y = bx - ab + b ) or ( y = bx - ab + b ).
If line AB contains the points 4 19 and -3 5 what is the slope of a line perpendicular to AB?
-1/2 or -0.50
If AB contains the points 6 -2 and -3 16 what is the slope of a line perpendicular to AB?
0.5
What is a perpendicular bisector of a line segment?
The perpendicular bisector of a line segment AB is the straight line perpendicular to AB through the midpoint of AB.
If line ab contains points 4 19 and -3 5 what is the slope of a line perpenduiclar to lineab?
negative 1/2
The curve y ax2 bx c passes through the point 1 2 and is tangent to the line y x at the origin Find ab and c?
y = ab^2+bx+c at point (1,2) y' = x since y' is also known as the slope, write the equation of point (1,2) at slope = X y- 2 = x (x-1) y= x^2-x+2 a=1 b=-1 c=2
