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Having said that, the slope is either -1/5 or 1/5.
It will have the same slope which is 2
After solving for y you will get y=1/5 x+1. The slope of this line is 1/5.
Slope-line form is: y = -4(x/5 + 1)
2x + 5y = 3 put into standard form wher y = mx + b and m = slope 5y + 2x = 3 5y = -2x + 3 y = -2/5x + 3/5 m = slope = -2/5
2/5 is the slope
6x-5y=30 6x-30=5y (6/5)x-6=y Therefore slope = 6/5 y-int = -6
4x+5y = 30 5y = -4x+30 y = -4/5x+6 in slope intercept form So the y intercept is 6.
It will have the same slope which is 2
Get in slope intercept form. 3X + 5Y = 15 5Y = -3X + 15 Y = -3/5X + 3 -3/5 is the slope of this line and the line parallel to this line
10x+5y = 25 5y = -10x+25 y = -2x+5 Therefore: the slope is -2 and the intercept is 5
4x-5y = 13 -5y = -4x+13 y = 4/5x-13/5 Slope = 4/5 or 0.8
3X + 5Y = 155Y = -3X + 15Y = (-3/5)X + 3The slope of this line is -3/5.The slope of a line perpendicular to it is 5/3.
5y - x = 10 5y = x + 10 or y = x/5 + 2 This is now the equaltion of the line in the standard form and the slope of the line is the coefficieint of x that is, 1/5 or 0.2
45
It is: minus 1.25
4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4
2x - 5y = -10 So 5y = 2x + 10 and therefore y = (2/5)*x plus something So the slope is 2/5 or 0.4