slope is -4/5 or -0.8 and there is no y intercept
Slope-line form is: y = -4(x/5 + 1)
Put in point slope form. Y =mX + c 4X + 5Y = - 10 5Y = - 4X - 10 Y = - (4/5)X - 2 =========== The slope(m) = - 4/5 --------------------------
Y = -2x + 5 so the slope of this equation, along with the slopes of parallel equations, is -2
4x-2y = 5 -2y = -4x+5 y = 2x-2.5 The slope is 2 and the y intercept is -2.5
slope = coefficient of x = -4
Parallel, the slope of the second equation is 4
slope is -4/5 or -0.8 and there is no y intercept
4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4
== == y = -x + 5
this is an equation of a line. it has a slope of 4/3 and a y-intercept of 5
Slope-line form is: y = -4(x/5 + 1)
Put in point slope form. Y =mX + c 4X + 5Y = - 10 5Y = - 4X - 10 Y = - (4/5)X - 2 =========== The slope(m) = - 4/5 --------------------------
Y = -2x + 5 so the slope of this equation, along with the slopes of parallel equations, is -2
4x-2y = 5 -2y = -4x+5 y = 2x-2.5 The slope is 2 and the y intercept is -2.5
The gradient (slope) of 3y = 4x+5 is 4/33y = 4x+5y = 4/3x+5/3y=mx+c(m = gradient)mx+c = 4/3x+5/3m = 4/3
4x-14