4x-5y+20 = 0 -5y = -4x-20 y = 4/5x+4 which is now in slope intercept form
Put in point slope form. Y =mX + c 4X + 5Y = - 10 5Y = - 4X - 10 Y = - (4/5)X - 2 =========== The slope(m) = - 4/5 --------------------------
(9,3)
-4x + 5y = 10Add 4x to each side:5y = 4x + 10Divide each side by 5:y = 0.8x + 2The graph of this equation is a straight line with [ slope = 0.8 ] and [ y-intercept = 2 ].
4x + 5y = 20 5y = -4x + 20 y = (-4/5)x + 20/5 Now that the equation has been rewritten in standard form, the slope is the cofficient of x, -4/5 [or -0.8]
4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4
45
It is: minus 1.25
4x-5y+20 = 0 -5y = -4x-20 y = 4/5x+4 which is now in slope intercept form
Put in point slope form. Y =mX + c 4X + 5Y = - 10 5Y = - 4X - 10 Y = - (4/5)X - 2 =========== The slope(m) = - 4/5 --------------------------
(9,3)
4x-5y = 13 -5y = -4x+13 y = 4/5x-13/5 Slope = 4/5 or 0.8
-4x + 5y = 10Add 4x to each side:5y = 4x + 10Divide each side by 5:y = 0.8x + 2The graph of this equation is a straight line with [ slope = 0.8 ] and [ y-intercept = 2 ].
4x + 5y = 20 5y = -4x + 20 y = (-4/5)x + 20/5 Now that the equation has been rewritten in standard form, the slope is the cofficient of x, -4/5 [or -0.8]
4x+5y = 30 5y = -4x+30 y = -4/5x+6 in slope intercept form So the y intercept is 6.
Slope-line form is: y = -4(x/5 + 1)
Let's see. 4X - 5Y = - 20 - 5Y = - 4X - 20 Y = 4/5X + 20 slope(m) = 4/5 Is positive