slope is -4/5 or -0.8 and there is no y intercept
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4x-5y+20 = 0 -5y = -4x-20 y = 4/5x+4 which is now in slope intercept form
Put in point slope form. Y =mX + c 4X + 5Y = - 10 5Y = - 4X - 10 Y = - (4/5)X - 2 =========== The slope(m) = - 4/5 --------------------------
(9,3)
-4x + 5y = 10Add 4x to each side:5y = 4x + 10Divide each side by 5:y = 0.8x + 2The graph of this equation is a straight line with [ slope = 0.8 ] and [ y-intercept = 2 ].
4x + 5y = 20 5y = -4x + 20 y = (-4/5)x + 20/5 Now that the equation has been rewritten in standard form, the slope is the cofficient of x, -4/5 [or -0.8]