If: 3x+y = -4 Then: y = -3x-4 and the slope of the line is -3
-3/4 if the question is 3x+4y
Point slope equation: Y=3X+12
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
The equation of the line given is in the form (y = 3x + 5), where the slope is the coefficient of (x). The slope of this line is 3. Since parallel lines have the same slope, the slope of any line parallel to this one would also be 3.
The equation in point slope of the line which passes through -2 -3 and is parallel to 3x plus 2y 10 is y=-1.5x.
If: 3x+y = -4 Then: y = -3x-4 and the slope of the line is -3
-3/4 if the question is 3x+4y
-9y + 3x + 2 = 0Put in point-slope form*:0 = -9y + 3x + 29y = 3x + 2 Subtract (-9y) from both sidesy = (1/3)x + (2/9) Divide both sides by 9 and reduce fractionsIt is now in point-slope form.m = (1/3)The slope is (1/3).*Point-slope form is y = mx + b where m is the slope and b is the y-intercept.
3X + 5Y = 155Y = -3X + 15Y = (-3/5)X + 3The slope of this line is -3/5.The slope of a line perpendicular to it is 5/3.
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
Get in slope intercept form. 3X + 5Y = 15 5Y = -3X + 15 Y = -3/5X + 3 -3/5 is the slope of this line and the line parallel to this line
Point slope equation: Y=3X+12
-3
Equation of given line: 3x + y = 15 or y = -3x + 15 Slope of given line = coefficient of x = -3 Slope of perperndicular = -1/(slope of given line) = -1 / (-3) = 1/3
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
y = 3x+8 which can be expressed in the form of 3x-y+8 = 0