If: 3x+y = -4 Then: y = -3x-4 and the slope of the line is -3
-3/4 if the question is 3x+4y
Point slope equation: Y=3X+12
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
The general equation of a line is: y = mx + b where m is the slope and b is the y-intercept. 3x + y = 4 y = -3x + 4 The slope is -3.
The equation in point slope of the line which passes through -2 -3 and is parallel to 3x plus 2y 10 is y=-1.5x.
If: 3x+y = -4 Then: y = -3x-4 and the slope of the line is -3
-3/4 if the question is 3x+4y
-9y + 3x + 2 = 0Put in point-slope form*:0 = -9y + 3x + 29y = 3x + 2 Subtract (-9y) from both sidesy = (1/3)x + (2/9) Divide both sides by 9 and reduce fractionsIt is now in point-slope form.m = (1/3)The slope is (1/3).*Point-slope form is y = mx + b where m is the slope and b is the y-intercept.
3X + 5Y = 155Y = -3X + 15Y = (-3/5)X + 3The slope of this line is -3/5.The slope of a line perpendicular to it is 5/3.
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
Get in slope intercept form. 3X + 5Y = 15 5Y = -3X + 15 Y = -3/5X + 3 -3/5 is the slope of this line and the line parallel to this line
Point slope equation: Y=3X+12
-3
Equation of given line: 3x + y = 15 or y = -3x + 15 Slope of given line = coefficient of x = -3 Slope of perperndicular = -1/(slope of given line) = -1 / (-3) = 1/3
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
y = 3x+8 which can be expressed in the form of 3x-y+8 = 0