0
There is no such number since a number 6 smaller than it would satisfy the requirements and it would be smaller.
The smallest positive number is 3 = 6*0 + 3
But as mentioned above, without the restriction of positivity, -3 would have done and would have been smaller.
And if -3 then -9
and then -15
etc.
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What is the smallest digit that can be placed in the blank so that 8-6935 can be divisible by 3?
2. To test a number to be divisible by 3, add up the digits and if the sum is divisible by 3, so is the original number. If not, the excess over a multiple of 3 gives the remainder when the original number is divided by 3. Subtract this remainder from 3 and this gives the smallest digit to replace the blank; unless the remainder is 0, in which case the blank can be replaced by a 0: 8 + 6 + 9 + 3 + 5 = 31 → 31 ÷ 3 = 10 remainder 1 Replace blank by 3 - 1 = 2: 826935 is divisible by 3
What is the smallest number which is divisible by 7 but has a remainder of 1 when divided by 1 2 3 4 5 and 6?
301
What is the smallest number that is divisible by 3 and 5?
15 is the smallest number divisible by both 3 and 5
What number is divisible by 5 with a remainder of 2 and divisible by 6 with a remainder of 3?
How about 27
Is 13 divisible by 3?
No 13 is not divisible by 3 because there would be a remainder of 1 and a number that is divisible by another should have no remainder
