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Q: What is the smallest prime number where each of the digits is a prime number 23 13 21 17?

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The number is 23.

Prime factorization: It is a method to express each number as the product of prime numbers.Step 1: Which prime number divide 75?Ans: 3 and 5.But, we should start with the smallest prime number which divides 75.75ÃƒÂ·3 = 25Step 2: Which prime number divide 25?Ans: 525ÃƒÂ·5 = 5Step 3: We have to continuously divide each quotient by a prime number until the quotient itself is a prime number.In step 2 we are left with 5(prime number) as a quotient.So, prime factorization of 75 = product of all the quotients = 3x5x5

23

In the prime factorisation of the number, each factor must appear an even number of times.In the prime factorisation of the number, each factor must appear an even number of times.In the prime factorisation of the number, each factor must appear an even number of times.In the prime factorisation of the number, each factor must appear an even number of times.

The smallest value Roman numeral using each symbol only once would be MCDXLIV = 1444

Related questions

The number is 23.

2520. The number needs to have a prime factorization of 23*32*5*7=2520.

By the sum of its digits: 10. By each of its individual digits: 11.

Any two prime numbers, of about 200 digits each, would work.Any two prime numbers, of about 200 digits each, would work.Any two prime numbers, of about 200 digits each, would work.Any two prime numbers, of about 200 digits each, would work.

838

The four numbers are: 113, 131, 151 and 191. For the product of the digits to be prime, the number must contain 2 ones - which greatly simplifies the exercise.

You had me until "product." The product of 4 digits can't be prime.

7? (13579)

It is 24578.

24578

773.

501396

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