The four numbers are: 113, 131, 151 and 191.
For the product of the digits to be prime, the number must contain 2 ones - which greatly simplifies the exercise.
The digits product of two digit has number four
0.12 Or 102 if you do not want to include non integers.
There are two numbers that satisfy the criteria. 38 and 83
4 x 578 = 2312 8 x 754 = 6032
If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.
You had me until "product." The product of 4 digits can't be prime.
Just multiply one pair of your numbers to give you a product, and then multiply their product by your third number.
Digits is how many numbers you have in a number. If you have the number 4 it has one digit if you have the number 20 it has two digits and if you have the number 558 it has three digits. So basically in the number 1085 it has 4 digits because there is 4 numbers in it, the numbers are 1,0,8 and 5. Hoped you understand.
101
It is: 100
Take the smallest 2-digit number (10), and see how many digits you get when you multiply it by itself.Also, take the largest possible 2-digit number (99), and see how many digits you get when you multiply it by itself.
Try the different numbers - there are only 11 after all - and multiply their digits. Or analyze the factors of the number 21.