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∙ 11y ago1*3*5*7*9 = 945
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∙ 11y ago2 x 3 x 5 = 30
The two smallest prime numbers are 2 & 3. Their product is thus, 2 x 3 = 6.
There are no such numbers. The smallest set of three consecutive composite numbers is {8, 9, 10} and the product of these numbers is 720.
2^3 * 5^3 = 1000
You would expect the answer to be 19 & 1 (giving just 19). However 21 & -1 give you a product of -21, and 23 & -3 gives -69. So, if you allow negative numbers, there is no limit.
2 x 3 x 5 = 30
The two smallest prime numbers are 2 & 3. Their product is thus, 2 x 3 = 6.
It is 27,000.
30
There are no such numbers. The smallest set of three consecutive composite numbers is {8, 9, 10} and the product of these numbers is 720.
Let the three numbers in GP: a/r, a, ar---------(A)Where '^' is power of . . .Sum of these numbers are:a/r +a +ar = 38a(1\r+1+r) = 38 ---- (1)Product of these numbers are:a^3 = 1728= (12)^3a = 12Putting the value of a in (1) you will get:12(1\r+1+r) = 38And factorising, we getr = 2/3 or r = 3/2Sub. the r and a value in (A), we get8,12,18 or 18,12,8. When a = 12And smallest no. is 8.
2^3 * 5^3 = 1000
You would expect the answer to be 19 & 1 (giving just 19). However 21 & -1 give you a product of -21, and 23 & -3 gives -69. So, if you allow negative numbers, there is no limit.
3, which can be divided by the odd numbers 1 and 3.
The product of 3 and 1 is 3. The product of any two numbers is simply the result of multiplying them together. 3 x 1 = 3.
2×3×5×7=210
The first prime numbers are 2, 3, 5, 7, 11. When multiplied together the product is 2310. It is the smallest number that has the first five numbers as its factors.