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Let the three numbers in GP: a/r, a, ar---------(A)
Where '^' is power of . . .

Sum of these numbers are:
a/r +a +ar = 38
a(1\r+1+r) = 38 ---- (1)
Product of these numbers are:
a^3 = 1728
= (12)^3
a = 12

Putting the value of a in (1) you will get:

12(1\r+1+r) = 38

And factorising, we get
r = 2/3 or r = 3/2

Sub. the r and a value in (A), we get

8,12,18 or 18,12,8. When a = 12

And smallest no. is 8.

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Q: Find the smallest number in a GP whose sum is 38 and product 1728?
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