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To solve the equation (x^2 + 12x - 35 = 0), we can use the quadratic formula (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a}), where (a = 1), (b = 12), and (c = -35). Plugging in these values gives us (x = \frac{{-12 \pm \sqrt{{12^2 - 4 \cdot 1 \cdot (-35)}}}}{2 \cdot 1}). This simplifies to (x = \frac{{-12 \pm \sqrt{{144 + 140}}}}{2}), or (x = \frac{{-12 \pm \sqrt{284}}}{2}). Thus, the solutions are (x = -6 \pm \sqrt{71}).

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2mo ago

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What is the trinomial pf x2-12x plus 35?

If you mean x^2 -12x+35 then it is a quadratic expression which can be factored in the form of (x-7)(x-5)


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x2-12x+35 = (x-5)(x-7)


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If you mean: x2+12x+35 then it is a quadratic expression that can be factored as: (x+5)(x+7)


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If you mean: x2-12x+35 then it is (x-7)(x-5) when factored


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divide 35 by 12


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To factor the trinomial ( x^2 - 12x + 35 ), we need to find two numbers that multiply to 35 and add to -12. The numbers -5 and -7 satisfy these conditions. Therefore, the trinomial can be factored as ( (x - 5)(x - 7) ), and one of the binomial factors is ( x - 5 ).


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