Without the inclusion of an equality sign the given expression can't be considered to be an equation
x2 - 10x - 6 = 2x + 1 Subtracting 2x + 1 from both sides gives: x2 - 12x - 7 = 0
x2+2x-63 = 0 When factorised: (x-7)(x+9) = 0 Therefore: x = 7 or x = -9
2x + 3 = 72x = 4x = 2
Not sure what you mean; that equation certainly has a solution.
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
x2 - 10x - 6 = 2x + 1 Subtracting 2x + 1 from both sides gives: x2 - 12x - 7 = 0
x2+2x-63 = (x-7)(x+9) when factored
x2+2x-63 = 0 When factorised: (x-7)(x+9) = 0 Therefore: x = 7 or x = -9
2x + 3 = 72x = 4x = 2
Not sure what you mean; that equation certainly has a solution.
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
It seems like there might be a typo or missing operators in your equation "x 2x 7." If you meant to write an equation, please clarify, such as "x + 2x = 7" or "x * 2x = 7." If it's "x + 2x = 7," then combining like terms gives you "3x = 7," leading to the solution ( x = \frac{7}{3} ). If it's another equation, please provide the correct format for a more accurate answer.
(2x - 10) + 7 = 52x - 3 = 52x = 8x = 4
x2-2x = 63 x2-2x -63 = 0 => x = -7 or x = 9 So x must = 9 Check: 92-18 = 63
A one solution equation is an equation that has exactly one unique solution. For example, the equation (2x + 3 = 7) can be solved by isolating (x): subtract 3 from both sides to get (2x = 4), and then divide by 2 to find (x = 2). This equation has only one solution, which is (x = 2).
The answer is (3.5)2 plus (4)2 equals 410.
If: y = 2x+k and y = x2-2x-7 Then: x2-2x-7 = 2x+k And so: x2-4x-7-k = 0 Using the discriminant of b2-4ac = 0 gives k a value of -11 Using the quadratic equation formula: x2-4x+4 = 0 gives x a duel value of 2 Therefore point of contact: (2, 0)