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x2 - 6x + 8 = 0

x2 - 4x - 2x + 8 = 0

x*(x - 4) - 2*(x - 4) = 0

(x - 2)*(x - 4) = 0

so (x - 2) = 0 or (x - 4) = 0

ie x = 2 or x = 4

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Q: What is the solution to x2-6x plus 8 equals 0?
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