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x + 7y = 33 multiply through by 3: 3x + 21y = 99 Subtract the second equation from the above equation: 23y = 92 So y = 4 Substituting this value of y in the first equation, x + 28 = 33 ie x = 5 The solution is (x,y) = (5,4)
−39x−6
If: 3x+6 = 12 Then: x = 2
3x - 2 = 9 3x = 9 + 2 = 11 x = 11/3
Yes