4
2x3 - 2x2 - x + 1 = 2x2(x -1) - (x - 1) = (x - 1)(2x2 -1) = (x - 1){[(sq. root of 2)(x)]2 -12} = (x - 1)[(sq. root of 2)(x) - 1][(sq. root of 2)(x) + 1]
0.3636
0.8
The fraction must be rationalized. Since it is the square root of x in the denominator, you are going to multiply the numerator and denominator by the square root of x. For simplicity of the problem, root will take the place of the symbol for square root: root(3y)/root(x) root(3y)*root(x)/root(x)*root(x) root(3xy)/x The simplified answer is going to be the square root of 3xy divided by x. Hope that helped.
4
f(x)=x2f -1(x)=sq. root(x)__________________y2=x [invert y](y2)-1=x = 1/y2=xsq. root(1/y2)= sq. root (x) [y can't be squared, root both sides](1/y)=sq. root(x)y-1=sq. root(x)
sq. root of 75 = sq. root of (25 x 3) = (sq. root of 25)(sq. root of 3) = 5(sq. root of 3)
Because: tan(60) = square root of 3
Square root of (1296) =Square root of (16 x 81)=SQ. root of (16) x Sq. root of (81) =4 x 9 =36
Find the factors of 484484= (4)(121)Square root of (484) = Sq. root (4 x 121) = Sq. root (4) x sq. root of (121) = 2(11) = 22
3.5714
2x3 - 2x2 - x + 1 = 2x2(x -1) - (x - 1) = (x - 1)(2x2 -1) = (x - 1){[(sq. root of 2)(x)]2 -12} = (x - 1)[(sq. root of 2)(x) - 1][(sq. root of 2)(x) + 1]
0.3636
0.8
(3 root 7) squared = (3 root 7) (3 root 7) = (3x 3) ( sq root 7 x 7) = 9 x sq root 49 = 9 x 7 = 63
2 x sq root 43