2*3 = 6 square miles
3..for a 3 dimensional square like a cube ... length, width and height and 2 for a 2 dimensional square ...length and width
The length and width would be equal to 22^2 = length^2 + width^2 444 = length^2 + width^2 Assuming the screen is a square, then 444 = 2length^2 222 = length^2 root(222) = length = width
Let the length be (2x+1) and the width be x: length*width = area (2x+1)*x = 21 square miles 2x2+x-21 = 0 Solving the above quadratic equation works out as: x = -7/2 or x = 3 it must be the latter because dimensions can't be negative. Therefore: length = 7 miles and width = 3 miles
width 1, length 10 width 2, length 5
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
Length: 6 miles width: 2 miles
length*width = 2*width*width i.e square the width and multiply by 2
3..for a 3 dimensional square like a cube ... length, width and height and 2 for a 2 dimensional square ...length and width
The length and width would be equal to 22^2 = length^2 + width^2 444 = length^2 + width^2 Assuming the screen is a square, then 444 = 2length^2 222 = length^2 root(222) = length = width
Let the length be (2x+1) and the width be x: length*width = area (2x+1)*x = 21 square miles 2x2+x-21 = 0 Solving the above quadratic equation works out as: x = -7/2 or x = 3 it must be the latter because dimensions can't be negative. Therefore: length = 7 miles and width = 3 miles
width 1, length 10 width 2, length 5
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
Length = 4, Width = 2
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
3" x 2" = 6 square inches. (just multiply length x width).
Its length is 1+ square root of 66 ft and its width is -1+ square root of 66 ft
The width is 2 !