The number is 3 less than the square root of 16 ie 3 less than 4, so it's 1.
The number is 1.
(3 + x)2 = 16 Square rooting both sides gives 3 + x = 4 x = 4 - 3 x = 1
32 + 42 = 9 + 16 = 25
225its 256, d square root being 16 which is 3 more dan d sum of d digits !!!
Sum = 3 x centre
The number is 1.
(3 + x)2 = 16 Square rooting both sides gives 3 + x = 4 x = 4 - 3 x = 1
They don't necesarily,3 is a triangular number and 10 is a triangular number. Their sum is 13 which is not a square number.They don't necesarily,3 is a triangular number and 10 is a triangular number. Their sum is 13 which is not a square number.They don't necesarily,3 is a triangular number and 10 is a triangular number. Their sum is 13 which is not a square number.They don't necesarily,3 is a triangular number and 10 is a triangular number. Their sum is 13 which is not a square number.
32 + 42 = 9 + 16 = 25
225its 256, d square root being 16 which is 3 more dan d sum of d digits !!!
Oh, dude, you're hitting me with some math riddles now? Alright, so the smallest square number that is the sum of two square numbers is 5, because 5 = 1^2 + 2^2. It's like a math puzzle for people who actually enjoy math, you know?
square of 5=5*5=25 Now sum of 23 and square of 5=23+25=48 Now one third of sum of 23 and square of 5=48/3 =16 Hence 16 is answer
There are two solution: -3 and +2.
A normal 3x3 magic square has a sum of 15. So you subtract 3 from each number in the square.
Sum = 3 x centre
The sum of a number plus 3 to the square root of 9 to the sum of 2 would equal -2. This is a math problem.
3 (n + 7) = 16