32 + 42 = 9 + 16 = 25
Triangle = sum of its 3 sides Square = sum of its 4 sides Rectangle = sum of its 4 sides
25= 5*5 = (3*3)+(4*4)
The number is 4 (4+3) * (4+3) = 49 (4+2) * (4+2) = 36 49 - 36 = 13
The numbers are 3, and 4.
The question is ambiguous.Does it want the sum of the squares, or the square of the sum ? They're different.Here are both:1). Sum of the squares: . (1)2 + (2)2 + (3)2 + (4)2 + (5)2 = 1 + 4 + 9 + 16 + 25 = 552). Square of the sum: . (1 + 2 + 3 + 4 + 5 )2 = (15)2 = 225
Triangle = sum of its 3 sides Square = sum of its 4 sides Rectangle = sum of its 4 sides
25= 5*5 = (3*3)+(4*4)
The number is 4 (4+3) * (4+3) = 49 (4+2) * (4+2) = 36 49 - 36 = 13
The numbers are 3, and 4.
The question is ambiguous.Does it want the sum of the squares, or the square of the sum ? They're different.Here are both:1). Sum of the squares: . (1)2 + (2)2 + (3)2 + (4)2 + (5)2 = 1 + 4 + 9 + 16 + 25 = 552). Square of the sum: . (1 + 2 + 3 + 4 + 5 )2 = (15)2 = 225
(3 + x)2 = 16 Square rooting both sides gives 3 + x = 4 x = 4 - 3 x = 1
2 + 3 + 4 + ... + 38 = 740
One example of two cubic numbers whose sum is a square number is (1^3 = 1) and (2^3 = 8). Their sum is (1 + 8 = 9), which is (3^2). Another example is (3^3 = 27) and (4^3 = 64); their sum is (27 + 64 = 91), which is not a perfect square. Thus, only the first example fits the criteria.
The number is 3 less than the square root of 16 ie 3 less than 4, so it's 1.
4
The 2nd square number is (2^2 = 4) and the 4th cube number is (4^3 = 64). Adding these together gives (4 + 64 = 68). Therefore, the sum of the 2nd square number and the 4th cube number is 68.
The sum of 3 plus 4 is 7.