1
The square root of 113 cannot be simplified further since 113 is a prime number and does not have any perfect square factors. Therefore, the simplified version of the square root of 113 remains as (\sqrt{113}). Its approximate decimal value is about 10.630, but in simplified radical form, it stays as (\sqrt{113}).
To find the length of side ( AB ) in the right triangle ( ABC ), we can use the Pythagorean theorem, which states that ( AB^2 = AC^2 + BC^2 ). Given ( AC = 7 ) and ( BC = 8 ), we have: [ AB^2 = 7^2 + 8^2 = 49 + 64 = 113 ] Taking the square root, we get: [ AB = \sqrt{113} ] Thus, the length of ( AB ) in simplest radical form is ( \sqrt{113} ).
113
It is already written in decimal form.
45/113 is already in its simplest form
Oh, dude, the square root of 113 in radical form is simply 113^(1/2). It's like saying, "Hey, what's the fancy way to write the square root of 113?" and I'm just here to tell you, it's 113^(1/2). So, there you go, fancy math lingo for ya!
The square root of 113 cannot be simplified further since 113 is a prime number and does not have any perfect square factors. Therefore, the simplified version of the square root of 113 remains as (\sqrt{113}). Its approximate decimal value is about 10.630, but in simplified radical form, it stays as (\sqrt{113}).
10.6301458 ==
The numbers are: 11 plus square root of 113 and 11 minus square root of 113
The square root of 15 as a fraction is 3 113/129.
10.6301, approx.
The square roots are +/- 10.6
113-2i sqr 17
The cube root of 113 is 4.834588127
It is the square root of 11.3
10.63014581 to eight decimal places. The calculator built-in to Windows would have given you the answer.
Don't see any "following" and this I's guessing is what you want? 113-(-68)^.5 = 113-((-1)(68))^.5 = 113-(68)^.5 (-1)^.5 = 113-i(68)^.5