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Assuming the vertex is 0,0 and the directrix is y=4

x^2=0

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Q: What is the standard form of the equation of the parabola with vertex 00 and directrix y4?
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Related questions

What is the standard equation of a parabola that opens up or down and whose vertex is at the origin?

focus , directrix


The is the extreme point of a parabola and is located halfway between the focus and directrix?

The vertex -- the closest point on the parabola to the directrix.


A parabola that opens upward?

Is a parabola whose directrix is below its vertex.


What is the extreme point of a parabola that is located halfway between the focus and directrix called?

It is the vertex of the parabola.


What is the standard equation for vertex at origin opens down 1 and 76 units between the vertex and focus?

Since the vertex is at the origin and the parabola opens downward, the equation of the parabola is x2 = 4py, where p < 0, and the axis of symmetry is the y-axis. So the focus is at y-axis at (0, p) and the directrix equation is y = -p. Now, what do you mean with 1 and 76 units? 1.76 units? If the distance of the vertex and the focus is 1.76 units, then p = -1.76, thus 4p = -7.04, then the equation of the parabola is x2 = -7.04y.


The is the extreme point of a parabola and is located halfway between the focus and directrix.?

This extreme point on the parabola is called the vertex. In math. a parabola is a U-shaped curve with a directrix, which is a fixed straight line.


The vertex is the extreme point of a parabola and is located halfway between the and directrix?

focus


How do you solve parabola equation having lb focus at 0 3?

There is not enough information. You need either the directrix or vertex (or some other item of information).


What does 4 stands for in equation of parabola square of square of y equals 4ax?

A parabola with an equation, y2 = 4ax has its vertex at the origin and opens to the right. It's not just the '4' that is important, it's '4a' that matters. This type of parabola has a directrix at x = -a, and a focus at (a, 0). By writing the equation as it is, the position of the directrix and focus are readily identifiable. For example, y2 = 2.4x doesn't say a great deal. Re-writing the equation of the parabola as y2 = 4*(0.6)x tells us immediately that the directrix is at x = -0.6 and the focus is at (0.6, 0)


The vertex is the extreme point of a parabola and is located halfway between the focus and?

focus directrix


What different information do you get from vertex form and quadratic equation in standard form?

The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.


What is the equation of a parabola with a vertex at 0 0 and a focus at 0 6?

The standard equation for a Parabola with is vertex at the origin (0,0) is, x2 = 4cy if the parabola opens vertically upwards/downwards, or y2 = 4cx when the parabola opens sideways. As the focus is at (0,6) then the focus is vertically above the vertex and we have an upward opening parabola. Note that c is the distance from the vertex to the focus and in this case has a value of 6 (a positive number). The equation is thus, x2 = 4*6y = 24y